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Crazy boy [7]
2 years ago
5

A.) Describe a transformation sequence that will transform quadrilateral ABCD into quadrilateral A’B’C’D’.

Mathematics
1 answer:
Mariulka [41]2 years ago
8 0

a.) The orientation of ABCD is clockwise, as is the orientation of A'B'C'D'. This means the transformation involves a even number of reflections (may be 0). The orientation of AB is North, and the orientation of A'B' is West, so a rotation of 90° CCW (or equivalent) is involved. We can find the point of intersection of the perpendicular bisectors of AA' and BB' (at (-1, -1)) to determine a suitable center of rotation.

ABCD can be transformed to A'B'C'D' by ...

  • rotation 90° CCW about the point (-1, -1)

b.) Rotation by 90° can also be accomplished by reflection across a diagonal line. Since we want the orientation to remain unchanged, we need another reflection to put the figure into its final position. A suitable alternate sequence for mapping ABCD to A'B'C'D' is ...

  • reflection across the line y=x
  • reflection across the line x=-1

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Endpoint: (1,7), midpoint: (-10,10)
algol [13]

The answer is (-21, 13) for The second endpoint.  

Let's start by calling the known endpoint L and the unknown K. We'll call the midpoint M. In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.

(Kx + Lx)/2 = Mx

(Kx + 1)/2 = -10

Kx + 1 = -20

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And now we do the same thing for y values

(Ky + Ly)/2 = My

(Ky + 7)/2 = 10

Ky + 7 = 20

Ky = 13

This gives us the final point of (-21, 13)

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The answer is "3 spots to the left"

The exponent of the final answer is -3
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Therefore, 0.003045 = 3.045 \times 10^{-3}

Answer: Choice C)
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