Question

The binomial (2x3 + 3y2)7 is shown in expanded form, but elements of several terms are missing. To complete the expansion, drag the missing parts to the places they belong.

Answer 1

${(2x^{3} + 3x^{2} )}^{7}$
EXPANDED: VERY LONG

$128x^{21} +1344x^{18} y^{2} +6048x^{15} y^{4} +15120x^{12} y^{6} +22680x^{9} y^{8} +20412x^{6} y^{10} +10206x^{3} y^{12} +2187y^{14}$

I used the Binomial Theorem, Which States
$(a + b)(a + b)= {a}^{2} + 2ab + {b}^{2}$
$({a}^{2} + 2ab + {b}^{2} )(a + b)={a}^{3} + 3 {a}^{2} b + 3a {b}^{2} + {b}^{3}$
$({a}^{3} + 3 {a}^{2} b + 3a {b}^{2} + {b}^{3}) \times (a + b) = i \: believe \: you \: get \: the \: pattern \: now$