<span>Visualize that out of the 90 caps, how many were green? 18 were green. So how many were not green? 90 caps - 18 caps = 72 caps. That means 72 caps were not green in that sporting good order. Therefore, the probability of one cap selected at random from the total 90 caps will not be green will be 72/90 which is roughly 0.8
or
80 percent. </span>
Answer:
Step-by-step explanation:
In a parallelogram, diagonals bisect each other.
7y - 2 = 5y + 4
7y - 2 - 5y = 4
2y - 2 = 4
2y = 4 +2
2y = 6
y = 6/2
y = 3
3x +2 = 23
3x = 23 - 2
3x = 21
x = 21/3
x = 7
Hey there!
<span>The numerator is the top part of the fraction and the
denominator is the bottom part of the fraction. </span>
For example, in the fraction 
, 1 would be the numerator and 2 would be the denominator.
Thank you!
Problem 1
<h3>Answer: B. M<3 would need to double.</h3>
Explanation: This is because angles 3 and 6 are congruent corresponding angles. Corresponding angles are congruent whenever we have parallel lines like this. If they weren't congruent, then the lines wouldn't be parallel. We would need to double angle 3 to keep up with angle 6.
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Problem 2
<h3>Answer: D. none of these sides are parallel</h3>
Explanation: We have angles A and C that are same side interior angles, but they add to A+C = 72+72 = 144, which is not 180. The same side interior angles must add to 180 degrees for parallel lines to form. This shows AB is not parallel to CD.
A similar situation happens with angles B and D, since B+D = 108+108 = 216. This also shows AB is not parallel to CD. We can rule out choices A and C.
Choice B is false because AD is a diagonal along with BC. The diagonals of any quadrilateral are never parallel as they intersect inside the quadrilateral. Parallel lines never intersect.
The only thing left is choice D. We would say that AC || BD, since A+B = 72+108 = 180 and C+D = 72+108 = 180, but this isn't listed as an answer choice.
Answer:
4
Step-by-step explanation:
Add each sample separately
A.17 B. 47 C. 39 D. 52 E. 45
Then you add them all together which totals 200 sick days
We know that they surveyed 5 schools and 10 students at random from each one. So we want to know the mean of sick days the students took not the schools in all.
So we divide 200/50
And get a mean of 4.
So each student took an average of 4 sick days each in the country.
