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Snowcat [4.5K]
3 years ago
12

Idk why I can’t get this ?! number two plz

Mathematics
1 answer:
Arturiano [62]3 years ago
7 0
The only possible outcome to this would be any number greater or less than 361 in the 300’s
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juan and debbie each earn 9 per hour at their "jobs." Debbie worked five hours more than juan during the week. if juan and debbi
Vaselesa [24]

Using a system of equations, it is found that Debbie worked 45 hours during the week.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are:

  • Variable x: Amount of hours worked by Juan.
  • Variable y: Amount of hours worked by Debbie.

Juan and Debbie each earn 9 per hour at their "jobs", and earned a total of 765 for the week, hence:

9x + 9y = 765

Simplifying the expression by 9:

x + y = 85 -> x = 85 - y.

Debbie worked five hours more than juan during the week, hence:

y = x + 5.

Since x = 85 - y, we replace in the expression:

y = 85 - y + 5.

2y = 90.

y = 45.

Debbie worked 45 hours during the week.

More can be learned about a system of equations at brainly.com/question/24342899

#SPJ1

3 0
2 years ago
I need help with this!
ruslelena [56]
|12| ÷ 2 • |-5|
= 12 ÷ 2 • 5
= 6 • 5
= 30
Absolute values just make the number positive if it is negative. The number stays positive if it’s positive.
7 0
3 years ago
Pls help with this (im not trying to be annoying)
ss7ja [257]
C(8)=29 you have to plug in 8 for n in the equation and solve. Hope this helps!!!

5 0
3 years ago
Which of the following could be the graph of the line y= -3x +2
frozen [14]

Answer:

Ans wer is 2nd quadrant

( - x line and + y line )

7 0
3 years ago
Define a variable write an equation and solve the problem. the width of a rectangle is 3 meters more than one-fourth its length.
sweet [91]

Let's assume

length of rectangle is L

width of rectangle is W

the width of a rectangle is 3 meters more than one-fourth its length

so,

W=3+\frac{1}{4} L

the perimeter is 10 meters more than twice its length

we know that

perimeter =2(L+W)

so, we get

2(L+W)=10+2L

now, we can simplify it

2L+2W=10+2L

subtract both sides by 2L

2L+2W-2L=10+2L-2L

2W=10

W=5

now, we can find L

5=3+\frac{1}{4} L

subtract both sides 3

5-3=3-3+\frac{1}{4} L

2=\frac{1}{4} L

multiply both sides by 4

4*2=4*\frac{1}{4} L

L=8

so,

length of rectangle is 8 meter

width of rectangle is 5 meter ............Answer

4 0
3 years ago
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