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Vsevolod [243]
2 years ago
11

How many times greater is the 7 digit in 873,240 than the 7 digit in 17,498?

Mathematics
1 answer:
Sonbull [250]2 years ago
3 0

Answer:

The 7 digit in 873,240 is 1000 times greater than the 7 digit in 17,498.

Step-by-step explanation:

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At a planetarium, adult tickets cost $2.50 each and children’s tickets cost $1.50 each. One day 408 tickets were sold in all, an
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Step-by-step explanation:

the answer is 2.50+1.50+733=737

5 0
3 years ago
1. A buoy floats 19 yards from the eastern most point of a boat and 15 yards from the western most point of a second boat. The a
Black_prince [1.1K]

The laws of cosines and law of sines can be used given that two sides

and an included angle, or two angles a side are known.

Response:

1. The other angles in the triangle formed by the buoy are approximately;

  • <u>31.1° and 40.9°</u>

2. Distance of the helicopter from the first island is approximately;

  • <u>14.5 miles</u>

<h3>How is the Law of Sines and Cosines used?</h3>

Given parameters are;

Distance of the buoy from the easternmost point of a boat = 19 yards

Distance of the buoy from the westernmost point of the other boat = 15 yards

Angle formed from the buoy to the two boats = 108°

Distance between the two boats, <em>d</em>, is given by the law of cosines, as follows;

d² = 19² + 15² - 2 × 19 × 15 × cos(108°) = 586 - 570·cos(108°)

d = √(586 - 570·cos(108°))

By the law of Sines, we have;

\dfrac{d}{sin(108^{\circ})} = \mathbf{\dfrac{15}{sin(Angle \ formed \ from \ the \ boat \ on \ the \ West, \ \theta_1)}}

Which gives;

sin(\theta_1) = \mathbf{ \dfrac{15 \times sin(108^{\circ})}{\sqrt{586 - 570 \cdot cos(108^{\circ})} }}

The o

\theta_1 = arcsin \left( \dfrac{15 \times sin(108^{\circ})}{\sqrt{586 - 570 \cdot cos(108^{\circ})} } \right) \approx   \mathbf{31.1^{\circ}}

The other angles formed in the triangle containing the buoy are;

  • θ₁ ≈ <u>31.1</u>
  • θ₂ ≈ 180° - 108° - 31.1° ≈<u> 40.9°</u>

2. Distance between the two islands = 20 miles

Angle of elevation with one island = 15°

Angle of elevation with the second island = 35°

Required:

The mileage (distance travelled) of the helicopter.

Solution:

Let <em>A</em> represent the island that has an angle of elevation to the helicopter

of 15°, and let <em>B</em> represent the other island.

Angle formed by the helicopter and the two island, θ, is found as follows;

θ = 180° - (15° + 35°) = 130°

By the Law of Sines, we have;

\dfrac{20}{sin(130^{\circ})} = \mathbf{ \dfrac{Distance \ from \  island \ A }{sin(35^{\circ})}}

Which gives;

Distance \ of \ helicopter \ from \  island \ A = \mathbf{ \dfrac{20}{sin(130^{\circ})} \times sin(35^{\circ})}

Mileage \ from \ island \ A =  \dfrac{20}{sin(130^{\circ})} \times sin(35^{\circ}) \times cos(15^{\circ}) \approx 14.5

  • The mileage of the helicopter from the first island is approximately <u>14.5 miles</u>

Learn more about the Law of Sines and Cosines here:

brainly.com/question/8242520

brainly.com/question/2491835

7 0
2 years ago
What is the solution in interval notation
san4es73 [151]
In interval notation<span>, you write this </span>solution<span> as (–2, 3]. not sure </span>
3 0
2 years ago
give an example of parallel lines in the real world. then describe how you could prove that lines are parallel.
worty [1.4K]

Answer:

An example would be the way that the shelves of a bookcase are positioned, they are parallel. Parallel lines are two or more lines that when drawn out infinitely long never intersect.

Step-by-step explanation:


6 0
2 years ago
What is the interquartile range (IQR) of the following data set?
OleMash [197]

Answer:

9

Step-by-step explanation:

Arrange data set

19, 4, 17, 3, 6, 5,5, 3, 11, 12, 3, 7, 15, 8, 8, 10,5, 3, 12, 41, 36

in ascending order

3, 3, 3, 3, <u>4, 5,</u> 5, 5, 6, 7, 8, 8, 10, 11, 12, <u>12, 15,</u> 17, 19, 36, 41

The median is Q_2=8

Q_1=\dfrac{4+5}{2}=4.5  

Q_3=\dfrac{12+15}{2}=13.5

Thus, the interquartile range is

Q_3-Q_1=13.5-4.5=9

4 0
3 years ago
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