Given:
$ 1.50 / gallon
1 gallon = 28 miles;
Solution:
$ 24.00 / $ 1.50 = 16 gallons
16 gallons x 28 miles = 448 miles
have a nice day:)
The best position for a cameraman to develop his shots with the best possible quality is any position that, without obstacles, allows him to have a panoramic viewing angle, with possible rotations to modify the degree of vision.
Thus, if the cameraman were in a circle, his ideal place would be in the center of it.
Learn more about circles in brainly.com/question/11833983
Answer with Step-by-step explanation:
We are given that
![f(x,y)=5 sinxy](https://tex.z-dn.net/?f=f%28x%2Cy%29%3D5%20sinxy)
Point=(x,y)=(0,2)
We have to find the maximum rate of change of f at given point.
![f_x(x,y)=5ycos(xy)](https://tex.z-dn.net/?f=f_x%28x%2Cy%29%3D5ycos%28xy%29)
![f_x(0,2)=5(2)cos0=10](https://tex.z-dn.net/?f=f_x%280%2C2%29%3D5%282%29cos0%3D10)
![f_y(x,y)=5xcosxy](https://tex.z-dn.net/?f=f_y%28x%2Cy%29%3D5xcosxy)
![f_y(0,2)=5(0)cos0=0](https://tex.z-dn.net/?f=f_y%280%2C2%29%3D5%280%29cos0%3D0)
![\Delta f(0,2)=f_x(0,2)+f_y(0,2)=10i+0j](https://tex.z-dn.net/?f=%5CDelta%20f%280%2C2%29%3Df_x%280%2C2%29%2Bf_y%280%2C2%29%3D10i%2B0j)
Maximum rate of change of f at point (0,2)=![\mid \Delta f(0,2)\mid=\sqrt{x^2+y^2}](https://tex.z-dn.net/?f=%5Cmid%20%5CDelta%20f%280%2C2%29%5Cmid%3D%5Csqrt%7Bx%5E2%2By%5E2%7D)
Where x=Coefficient of i
y=Coefficient of j
By using the formula
Maximum rate of change of f at point (0,2)=![\sqrt{(10)^2+0}=10](https://tex.z-dn.net/?f=%5Csqrt%7B%2810%29%5E2%2B0%7D%3D10)
Direction of maximum rate of change of f=![\Delta\har{f}=\frac{\Delta f(0,2)}{\mid\Delta f(0,2)\mid}=\frac{10i}{10}=i](https://tex.z-dn.net/?f=%5CDelta%5Char%7Bf%7D%3D%5Cfrac%7B%5CDelta%20f%280%2C2%29%7D%7B%5Cmid%5CDelta%20f%280%2C2%29%5Cmid%7D%3D%5Cfrac%7B10i%7D%7B10%7D%3Di)