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Natalka [10]
3 years ago
13

The sophomore class sold a total of 700 adult and student tickets to the school play. Adult tickets sold for $4.50 each and stud

ent tickets cost $2.oo each. If they took in a total of $1,200, which system of equations can be used to find x, the number of student tickets sold, and y; the number of adult tickets sold?
A: x+y = 1200
2x+4.5y =700

B: x+y=700
2x+4.5y=1200

C: x+y=1200
x+y = 700

Mathematics
2 answers:
mars1129 [50]3 years ago
6 0

Answer:

some answers

sergiy2304 [10]3 years ago
3 0
The answer is <span>
B: x+y=700
2x+4.5y=1200
</span>

<span>x - the number of student tickets sold,
y - the number of adult tickets sold

The total number of sold tickets is 700:
x + y = 700

</span><span>Adult tickets sold for $4.50 each and student tickets cost $2.oo each. If they took in a total of $1,200:
2x + 4.50y = 1200

The system of equations is:
</span>x + y = 700
2x + 4.50y = 1200
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In a state lottery 25 balls numbered from 1 to 25 and placed in machine. 6 numbers randomly drawn. And here is the chart what ca
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Answer:

win $5,000: P = 0.0006437

win $50: P = 0.6196

Step-by-step explanation:

To win $5,000, we must have a match of 5 numbers.

So from the 6 numbers, we correcly choose 5 numbers and miss 1 number. The probability of matching or not each of the 6 numbers is:

First number: P = 6/25

Second number: P = 5/24

Third number: P = 4/23

Fourth number: P = 3/22

Fifth number: P = 2/21

Sixth number: P = 19/20 (wrong number)

As the 5 correct numbers can be any of the 6, we also have to multiply the probabilities by a combination of 6 choose 5:

c(6,5) = 6!/5! = 6

So the final probability is:

P = 6 * (6/25) * (5/24) * (4/23) * (3/22) * (2/21) * (19/20) = 0.0006437

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First number: P = 6/25

Second number: P = 5/24

Third number: P = 22/23 (wrong number)

Fourth number: P = 21/22 (wrong number)

Fifth number: P = 20/21 (wrong number)

Sixth number: P = 19/20 (wrong number)

As the 2 correct numbers can be any of the 6, we also have to multiply the probabilities by a combination of 6 choose 2:

c(6,2) = 6!/(4!*2!) = 6*5/2 = 15

So the final probability is:

P = 15 * (6/25) * (5/24) * (22/23) * (21/22) * (20/21) * (19/20) = 0.6196

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