Following transformations on Triangle ABC will result in the Triangle A'B'C'
a) Reflection the triangle across x-axis
b) Shift towards Right by 2 units
c) Shift upwards by 6 units
In Triangle ABC, the coordinates of the vertices are:
A (1,9)
B (3, 12)
C (4, 4)
In Triangle A'B'C, the coordinates of the vertices are:
A' (3, -3)
B' (5, -6)
C' (6, 2)
First consider point A of Triangle ABC.
Coordinate of A are (1, 9). If we reflect it across x-axis the coordinate of new point will be (1, -9). Moving it 2 units to right will result in the point (3, -9). Moving it 6 units up will result in the point (3,-3) which are the coordinates of point A'.
Coordinates of B are (3,12). Reflecting it across x-axis, we get the new point (3, -12). Moving 2 units towards right, the point is translated to (5, -12). Moving 6 units up we get the point (5, -6), which are the coordinate of B'.
The same way C is translated to C'.
Thus the set of transformations applied on ABC to get A'B'C' are:
a) Reflection the triangle across x-axis
b) Shift towards Right by 2 units
c) Shift upwards by 6 units
240/4=60 so 60x5=300. Traveled 300 miles in 5 hours
Answer:
code = 56
Step-by-step explanation:
E = GCF(22,30) = 2
F = LCM(3,8) = 24
Given
3 * (7+10) = G +30 => 51 = G + 30 => G = 21
5 * (3+H) = 15 + 45 => 3+H = (60/5) = 12 => H = 12 - 3 = 9
Sum E + F + G + H = 2 + 24 + 21 + 9 = 56
I think the should be <span><span><span>a2</span><span>b4</span></span>c</span><span>(3)</span><span>=<span><span><span>3<span>a2</span></span><span>b4</span></span><span>c
i hoped it's helped
thx ba bye </span></span></span>
