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2 years ago

A number is less than 30 but greater than 10.

Mathematics

1 answer:

GenaCL600 [577]2 years ago

7 0

The answer is 16 and 26. Both are less than 30 and greater than 10 and have 6 in the one’s place.

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Hyxetdryufgukhchfxrdtygujhftyuhuhyguhjygyu

nikklg [1K]

Answer:

so the answer is: eijieljnqwsmiqwmx

did i answer it correctly let me know

Step-by-step explanation:

Destroy your keyboard by smashing each random word on the poor broken keyboard

6 0

2 years ago

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the equation of line t is 6x+5y=3, and the equation of line q is 5x-6y=0. Which statement about the two lines is true?

nekit [7.7K]

The correct answer would be: 6x+5y=3. I am not entirely sure, but that's what I believe is the correct answer.-Hope this helped!

4 0

2 years ago

suppose that a water fountain produces a stream of water that follows the shape of a parabola. assigning the origin of a coordin

Readme [11.4K]

The quadratic regression equation for the stream of water is $y=-0.139x^{2} +1.667x$ {parabola}

Given that the water stream produced by fountain is parabola

Vertex of parabola is (6,5) , parbola is facing downward,axis of symmetry of parabola is x=6 and parabola passes through (0,0)

according to symmetry the third point on the parabola is (12,0)

General equation for a parabola⇒ Y=-4a $X^{2}$

⇒(y-5)=-4a $(x-6)^{2}$ { as the Vertex of parabola is (6,5) }

⇒(y-5)=-4a( $x^{2} +36-12x$ )

subtituting (0,0) in the equation to get the value of a

⇒-5=-4a(36)

⇒ a= $\frac{-5}{144}$

equation of parabola⇒(y-5)=-4( $\frac{5}{144}$ ) $(x-6)^{2}$

Therefore,The quadratic regression equation for the stream of water is $y=-0.139x^{2} +1.667x$

Learn more about parabola here:

brainly.com/question/21685473

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3 0

1 year ago

HELP ASAP

Andrei [34K]

Answer:

$radius = \sqrt{13}$ or $radius = 3.61$

Step-by-step explanation:

Given

Points:

A(-3,2) and B(-2,3)

Required

Determine the radius of the circle

First, we have to determine the center of the circle;

Since the circle has its center on the x axis; the coordinates of the center is;

$Center = (x,0)$

Next is to determine the value of x through the formula of radius;

$radius = \sqrt{(x_1 - x)^2 + (y_1 - y)^2} = \sqrt{(x_2 - x)^2 + (y_2 - y)^2}$

Considering the given points

$A(x_1,y_1) = A(-3,2)$

$B(x_2,y_2) = B(-2,3)$

$Center(x,y) =Center (x,0)$

Substitute values for $x,y,x_1,y_1,x_2,y_2$ in the above formula

We have:

$\sqrt{(-3 - x)^2 + (2 - 0)^2} = \sqrt{(-2 - x)^2 + (3 - 0)^2}$

Evaluate the brackets

$\sqrt{(-(3 + x))^2 + 2^2} = \sqrt{(-(2 + x))^2 + 3 ^2}$

$\sqrt{(-(3 + x))^2 + 4} = \sqrt{(-(2 + x))^2 + 9}$

Eva;uate all squares

$\sqrt{(-(3 + x))(-(3 + x)) + 4} = \sqrt{(-(2 + x))(-(2 + x)) + 9}$

$\sqrt{(3 + x)(3 + x) + 4} = \sqrt{(2 + x)(2 + x) + 9}$

Take square of both sides

$(3 + x)(3 + x) + 4 = (2 + x)(2 + x) + 9$

Evaluate the brackets

$3(3 + x) +x(3 + x) + 4 = 2(2 + x) +x(2 + x) + 9$

$9 + 3x +3x + x^2 + 4 = 4 + 2x +2x + x^2 + 9$

$9 + 6x + x^2 + 4 = 4 + 4x + x^2 + 9$

Collect Like Terms

$6x -4x + x^2 -x^2 = 4 -4 + 9 - 9$

$2x = 0$

Divide both sides by 2

$x = 0$

This implies the the center of the circle is

$Center = (x,0)$

Substitute 0 for x

$Center = (0,0)$

Substitute 0 for x and y in any of the radius formula

$radius = \sqrt{(x_1 - 0)^2 + (y_1 - 0)^2}$

$radius = \sqrt{(x_1)^2 + (y_1)^2}$

Considering that we used x1 and y1;

In this case we have that; $A(x_1,y_1) = A(-3,2)$

Substitute -3 for x1 and 2 for y1

$radius = \sqrt{(-3)^2 + (2)^2}$

$radius = \sqrt{13}$

$radius = 3.61$ ---<em>Approximated</em>

7 0

3 years ago

Find the value of x. Give reasons to justify your solution-

LuckyWell [14K]

Answer:

x = 34

Step-by-step explanation:

∠ PSR and ∠ TSU are vertical angles and congruent, then

∠ PSR = 4x, thus ∠ PSQ = x

The exterior angle of a triangle is equal to the 2 opposite interior angles.

∠ SQR is an exterior angle of Δ PQS , thus

x + x = 68

2x = 68 ( divide both sides by 2 )

x = 34

7 0

2 years ago

Read 2 more answers