Answer:
to use integers for certain problems and equation on math, i can also use it for future use in life in case i need it, Its very helpful to learn since it isnt that complicated nor hard, its just a good skill to keep in mind as a student.
![\begin{array}{rrrrr} 10x&-&18y&=&2\\ -5x&+&9y&=&-1 \end{array}~\hfill \implies ~\hfill \stackrel{\textit{second equation }\times 2}{ \begin{array}{rrrrr} 10x&-&18y&=&2\\ 2(-5x&+&9y&)=&2(-1) \end{array}} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{rrrrr} 10x&-&18y&=&2\\ -10x&+&18y&=&-2\\\cline{1-5} 0&+&0&=&0 \end{array}\qquad \impliedby \textit{another way of saying \underline{infinite solutions}}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brrrrr%7D%2010x%26-%2618y%26%3D%262%5C%5C%20-5x%26%2B%269y%26%3D%26-1%20%5Cend%7Barray%7D~%5Chfill%20%5Cimplies%20~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Bsecond%20equation%20%7D%5Ctimes%202%7D%7B%20%5Cbegin%7Barray%7D%7Brrrrr%7D%2010x%26-%2618y%26%3D%262%5C%5C%202%28-5x%26%2B%269y%26%29%3D%262%28-1%29%20%5Cend%7Barray%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Brrrrr%7D%2010x%26-%2618y%26%3D%262%5C%5C%20-10x%26%2B%2618y%26%3D%26-2%5C%5C%5Ccline%7B1-5%7D%200%26%2B%260%26%3D%260%20%5Cend%7Barray%7D%5Cqquad%20%5Cimpliedby%20%5Ctextit%7Banother%20way%20of%20saying%20%5Cunderline%7Binfinite%20solutions%7D%7D)
if we were to solve both equations for "y", we'd get
notice, the 1st equation is really the 2nd in disguise, since both lines are just pancaked on top of each other, every point in the lines is a solution or an intersection, and since both go to infinity, well, there you have it.
B. Reflect the graph about the y-axis and translate one unit up
The answer to this question is 0.64 because you have to divide hope this helps you
Answer:
Directrix equation: y = 11/2
y = k - c = 6 - 1/2 = 11/2
Step-by-step explanation:
y=(1/2) x^2+6x+24
factor this
y = (1/2)* [ x^2 + 12x ] + 24
y = (1/2)* [ x^2 + 12x + 36 - 36] + 24
y = (1/2)* [ (x + 6)^2 - 36] + 24
y = (1/2)* (x + 6)^2 - 18 + 24
y = (1/2)* (x + 6)^2 + 6
y - 6 = (1/2)* (x + 6)^2
2*(y - 6) = (x + 6)^2
4c = 2, (h, k) = (-6, 6)
c = 1/2
Directrix equation: y = k - c = 6 - 1/2 = 11/2
