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ivolga24 [154]
3 years ago
10

If u need points just answer this

Mathematics
2 answers:
Dafna1 [17]3 years ago
7 0

Hello i need points so I’m answereing this :)

sasho [114]3 years ago
5 0

OK im answering ............................................................................................................

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Which is a tangent of circle P?pls helpt ASAP!!!!
oee [108]
<h3>Answer: Choice C)  line n</h3>

Explanation:

Tangent lines touch the circle at exactly one point.

7 0
2 years ago
A cake has two layers. Each layer is a regular hexagonal prism. You cut and remove a slice that takes away one face of each pris
elena-s [515]

The volume of the slice is 129 in^3 and that of the remaining cake is 374. 4 in^3

<h3>How to determine the volume </h3>

Using the formula:

Volume = 3abh

Where a = apothem length

b = length of the side of the base

h =height of the prism

Substitute values from the diagram into the formula

Volume = 3 × 5 × 4.3 × 2

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Volume of the remaining cake

Volume = 3abh

Volume = 3× 5.2 × 4 × 6

Volume = 374. 4 in^3

Thus, the volume of the slice is 129 in^3 and that of the remaining cake is 374. 4 in^3

Learn about volume of a hexagonal prism here:

brainly.com/question/9647193

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8 0
2 years ago
What is the explicit formula for this arithmetic sequence?<br>3,9,15,21,27​
denis-greek [22]

Answer:

Step-by-step explanation:

Formula is to add 6. As you can see: 3+6=9; 9+6=15; 15+6=21 and 21+6=27.

I hope this was helpful.

8 0
3 years ago
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Which line is parallel to 8x+2y=12
Nat2105 [25]

x=3/2-1/4

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move the variable to the right side and change the sign.

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divide both sides of the equation by 8

x=3/2-1/4y

the final solution is

x=3/2-1/4y

4 0
3 years ago
Read 2 more answers
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iogann1982 [59]
\bf =ae^{kt}\qquad &#10;\begin{cases}&#10;1994\impliedby \textit{year 0, starting point}\\&#10;t=0\qquad P=182&#10;\end{cases}\implies 182=ae^{k0}&#10;\\\\\\&#10;182=a\cdot e^0\implies 182=a\cdot 1\implies 182=a&#10;\\\\\\&#10;thus\qquad P=182e^{kt}\\\\&#10;-------------------------------\\\\

\bf P=182e^{kt}\qquad &#10;\begin{cases}&#10;2002\impliedby \textit{8 years later}\\&#10;t=8\qquad P=186&#10;\end{cases}\implies 186=182e^{k8}&#10;\\\\\\&#10;\cfrac{186}{182}=e^{8k}\implies ln\left( \frac{93}{91} \right)=ln(e^{8k})\implies ln\left( \frac{93}{91} \right)=8k&#10;\\\\\\&#10;\cfrac{ln\left( \frac{93}{91} \right)}{8}=k\implies 0.0027\approx k\implies \boxed{P=182e^{0.0027t}}

what's the population in 2004?  well,  from 1994 to 2004 is 10 years later, so t = 10

plug that in, to get P for 2004
3 0
3 years ago
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