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Finger [1]
3 years ago
12

For each of the following situations, identify the response variable and the populations to be compared, and give

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
4 0

Answer:

leifjdfhjejfr8fr

Step-by-step explanation:

lets gohdffddendhcfnd

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And here is the other one.
LUCKY_DIMON [66]
Since BD bisects angle ABC, that means angle ABD and angle CBD are equal to each other. With that set up the equation to solve for x like this:

-4x+33 = 2x+81
-2x -2x
————————
-6x +33 = 81
-33 -33
————————
-6x = 48
————- (divide by -6)
-6

x = -8


Now substitute that to ABD
-4(-8) +33
32 +33
=65

here’s CBD
2(-8) + 81
-16 + 81
=65

Finally angle ABC will be double the amount of ABD or CBD so 65 times 2 is 130.

ANSWERS: (angles)
ABD and CBD: 65
ABC: 130

3 0
3 years ago
Malia is on a road trip. During the first five minutes of Malia's trips he sees 18 cars and 6 trucks. Assuming this ratio of car
Colt1911 [192]
If you divide 18 and 6 you will get three so three times 1254 equals 3,762 card that he saw
6 0
3 years ago
Read 2 more answers
How to solve this?<br>\int \frac { 4 - 3 x ^ { 2 } } { ( 3 x ^ { 2 } + 4 ) ^ { 2 } } d x​
ivanzaharov [21]

\Large \mathbb{SOLUTION:}

\begin{array}{l} \displaystyle \int \dfrac{4 - 3x^2}{(3x^2 + 4)^2} dx \\ \\ = \displaystyle \int \dfrac{4 - 3x^2}{x^2\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ = \displaystyle \int \dfrac{\dfrac{4}{x^2} - 3}{\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ \text{Let }u = 3x + \dfrac{4}{x} \implies du = \left(3 - \dfrac{4}{x^2}\right)\ dx \\ \\ \text{So the integral becomes}  \\ \\ = \displaystyle -\int \dfrac{du}{u^2} \\ \\ = -\dfrac{u^{-2 + 1}}{-2 + 1} + C \\ \\ = \dfrac{1}{u} + C \\ \\ = \dfrac{1}{3x + \dfrac{4}{x}} + C \\ \\ = \boxed{\dfrac{x}{3x^2 + 4} + C}\end{array}

5 0
3 years ago
A rectangle field is 350 meters long and 300 meters wide. What is the area of the field in square kilometers
balu736 [363]

Okay, so a kilometer=1000 meters, knowing that we can multiply 350*300 for the area, which would give us 105000 meters squared, then we divide 105000 by 1000, giving us 105 square kilometers.

4 0
3 years ago
On a test that has a normal distribution, a score of 19 falls one standard deviation below the mean, and a score of 40 falls two
nexus9112 [7]

Hi there!

We can use the following equation:

\large\boxed{z = \frac{x-\mu}{\sigma}}

z = amount of standard deviations away a value is from the mean (z-score)

σ = standard deviation

x = value

μ = mean

Plug in the knowns for both and rearrange to solve for the mean:

-1 = \frac{19-\mu}{\sigma}\\\\-\sigma = 19 - \mu\\\\ \sigma = -19 + \mu

Other given:

2 = \frac{40-\mu}{\sigma}\\\\2\sigma = 40- \mu\\\\ \sigma = 20 - \frac{\mu}{2}

Set both equal to each other and solve:

-19 + \mu = 20 - \frac{\mu}{2}\\\\\frac{3\mu}{2} = 39 \\\\3\mu = 78 \\\\\boxed{\mu = 26 }

5 0
2 years ago
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