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Finger [1]
2 years ago
12

For each of the following situations, identify the response variable and the populations to be compared, and give

Mathematics
1 answer:
zhannawk [14.2K]2 years ago
4 0

Answer:

leifjdfhjejfr8fr

Step-by-step explanation:

lets gohdffddendhcfnd

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Keli has 26 roses and 73 carnations. She will put an assortment of 6 flowers in each vase. How many vases will she need for her
Irina18 [472]
Add 26 and 73 = 99 then divide 99 by 6 = 16.5 which is 17 vases
8 0
3 years ago
Find vertex and y- intercept and x-intercept in x^2 -2x-15
AfilCa [17]
It would be (x-5)(x+3)

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3 years ago
What’s this <br> hdhshxbbsncjdkckskxbsh
7nadin3 [17]

Answer:

i dunno what that means but i think maybe your keyboard broke so the type of letters is random??

5 0
3 years ago
Solve for .6u+7u-16=-81<br> Simplify your answer as much as possible.
Vesnalui [34]

Answer:

6u+7u-16=-81

We simplify the equation to the form, which is simple to understand

6u+7u-16=-81

We move all terms containing u to the left and all other terms to the right.

+6u+7u=-81+16

We simplify left and right side of the equation.

+13u=-65

We divide both sides of the equation by 13 to get u.

u=-5

Step-by-step explanation:

I think i did it correct

7 0
3 years ago
Read 2 more answers
The function ƒ(x) = (x − 1)^2 + 5 is not one-to-one. Find a portion of the domain where the function is one-to-one and find an i
melisa1 [442]

Answer:

f(x)=(x-1)^2+5 with domain x>1 and range y>5 has inverse g(x)=sqrt(x-5)+1 with domain x>5 and range y>1.

Step-by-step explanation:

The function is a parabola when graphed. It is in vertex form f(x)=a(x-h)^2+k where (h,k) is vertex and a tells us if it's reflected or not or if it's stretched. The thing we need to notice is the vertex because if we cut the graph with a vertical line here the curve will be one to one. So the vertex is (1,5). Let's restrict the domain so x >1.

* if x>1, then x-1>0.

* Also since the parabola opens up, then y>5.

So let's solve y=(x-1)^2+5 for x.

Subtract 5 on both sides:

y-5=(x-1)^2

Take square root of both sides:

Plus/minus sqrt(y-5)=x-1

We want x-1>0:

Sqrt(y-5)=x-1

Add 1 on both sides:

Sqrt(y-5)+1=x

Swap x and y:

Sqrt(x-5)+1=y

x>5

y>1

3 0
3 years ago
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