Step-by-step explanation:
Consider a function
f
(
x
)
which is twice differentiable. The graph of such a function will be concave upwards in the intervals where the second derivative is positive and the graph will be concave downwards in the intervals where the second derivative is negative. To find these intervals we need to find the inflection points i.e. the x-values where the second derivative is 0.
<span>Sometimes. The following figure shows.</span>
To convert this equation into slope intercept form simply distribute the number of -2 and put it in
Y = mx + b form
Y + 4 = -2(X-1)
Y + 4 = -2x + 2
Y = -2X + 2 - 4
Y = -2X - 2
I believe this is the solution in slope intercept form.
