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Alex73 [517]
4 years ago
5

If one leg of a right triangle is 3 cm, and the hypotenuse is 5 cm, what is the length of the other leg?

Mathematics
1 answer:
torisob [31]4 years ago
3 0

Answer: 4cm

Step-by-step explanation:

Let the unknown side be x , then

from Pythagoras rule :

x^{2} = 5^{2} - 3^{2}

x^{2} = 25 - 9

x^{2} = 16

x = 4

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Answer:

A. Ratios are both identical

Step-by-step explanation:

sin x = 3/5

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3 years ago
The measure of central angle QRS is StartFraction 8 pi Over 9 EndFraction radians. What is the area of the shaded sector? 36Pi u
MArishka [77]

The question is missing the figure. So, it is attached below.

Answer:

Area of the shaded sector is <u>144π units squared</u>.

Step-by-step explanation:

Given:

Central angle of the sector is, \theta=\frac{8\pi}{9}\ rad

Radius of the circle is, R=18\ units

We know that, area of a sector of a circle of radius 'R' and central angle \theta is given as:

A=\frac{1}{2}R^2\theta

Plug in \theta=\frac{8\pi}{9},R=18. This gives,

A=\frac{1}{2}\times (18)^2\times \frac{8\pi}{9}\\\\A=(\frac{324\times 4}{9})\pi\\\\A=(36\times 4)\pi\\\\A=144\pi\ units^2

Therefore, the area of the shaded sector is 144π units squared.

5 0
4 years ago
Read 2 more answers
A coin is flipped eight times where each flip comes up either heads or tails. How many possible outcomes a) are there in total?
attashe74 [19]

Answer:

There are 256 ways in total.

There are 56 possible outcomes contain exactly three heads.

The possible outcomes contain at least three heads is 219.

The possible outcomes contain the same number of heads and tails are 70.

Step-by-step explanation:

Consider the provided information.

A coin is flipped eight times where each flip comes up either heads or tails.

Part (a) How many possible outcomes are there in total?

Each time we flip a coin it comes up either heads or tail.

Therefore the total number of ways are:

2\times 2\times 2\times 2\times 2\times 2\times 2\times 2=2^8=256

Hence, there are 256 ways in total.

Part (b) contain exactly three heads?

We want exactly 3 heads, therefore,

n=8 and r=3

According to the definition of combination: \binom{n}{r}=\frac{n!}{r!(n-r)!}

\binom{8}{3}=\frac{8!}{3!(5)!}=56

Hence, there are 56 possible outcomes contain exactly three heads.

Part (c) contain at least three heads?

For 3 heads: \binom{8}{3}=\frac{8!}{3!(5)!}=56

For 4 heads: \binom{8}{4}=\frac{8!}{4!(4)!}=70

For 5 heads: \binom{8}{5}=\frac{8!}{5!(3)!}=56

For 6 heads: \binom{8}{6}=\frac{8!}{6!(2)!}=28

For 7 heads: \binom{8}{7}=\frac{8!}{7!(1)!}=8

For 8 heads: \binom{8}{8}=1

Now add them as shown:

56+70+56+28+8+1=219

Hence, the possible outcomes contain at least three heads is 219.

Part (d) contain the same number of heads and tails?

Same number of heads and tails means that the value of r=4.

Therefore,

\binom{8}{4}=\frac{8!}{4!(4)!}=70

Hence, the possible outcomes contain the same number of heads and tails are 70.

6 0
3 years ago
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Harrizon [31]
Hi !! the correct answer would be the last option, due to the fact that -2 and 2 both have the same absolute value, hope it helps !! :]
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3 years ago
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Solve for x.
exis [7]

Answer:

11.2

Step-by-step explanation:

tan( <em>angle </em>) = <em>opposite / adjacent</em>

8 0
3 years ago
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