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3 years ago

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There are 8 orange candies and 4 blue candies you select one candy eat it and then select another find P(you select first an ora

nge candy and then a blue candy )

2 answers:

Savatey [412]3 years ago

4 0

Orange first = 9/13

Blue next = 4/12

<span>P(both) = (9/13)*(4/12) </span>
<span>P(both) = 3/13 ~ 0.23</span>

aksik [14]3 years ago

4 0

Answer: 8/33 Apex

Just took the quiz I hope this helps good luck

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Solve irrational equation pls

rusak2 [61]

$\hbox{Domain:}\\
x^2+x-2\geq0 \wedge x^2-4x+3\geq0 \wedge x^2-1\geq0\\
x^2-x+2x-2\geq0 \wedge x^2-x-3x+3\geq0 \wedge x^2\geq1\\
x(x-1)+2(x-1)\geq 0 \wedge x(x-1)-3(x-1)\geq0 \wedge (x\geq 1 \vee x\leq-1)\\
(x+2)(x-1)\geq0 \wedge (x-3)(x-1)\geq0\wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\
x\in(-\infty,-2\rangle\cup\langle1,\infty) \wedge x\in(-\infty,1\rangle \cup\langle3,\infty) \wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\
x\in(-\infty,-2\rangle\cup\langle3,\infty)$

$
\sqrt{x^2+x-2}+\sqrt{x^2-4x+3}=\sqrt{x^2-1}\\
x^2-1=x^2+x-2+2\sqrt{(x^2+x-2)(x^2-4x+3)}+x^2-4x+3\\
2\sqrt{(x^2+x-2)(x^2-4x+3)}=-x^2+3x-2\\
\sqrt{(x^2+x-2)(x^2-4x+3)}=\dfrac{-x^2+3x-2}{2}\\
(x^2+x-2)(x^2-4x+3)=\left(\dfrac{-x^2+3x-2}{2}\right)^2\\
(x+2)(x-1)(x-3)(x-1)=\left(\dfrac{-x^2+x+2x-2}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\left(\dfrac{-x(x-1)+2(x-1)}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\left(\dfrac{-(x-2)(x-1)}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\dfrac{(x-2)^2(x-1)^2}{4}\\
4(x+2)(x-3)(x-1)^2=(x-2)^2(x-1)^2\\$
$
4(x+2)(x-3)(x-1)^2-(x-2)^2(x-1)^2=0\\
(x-1)^2(4(x+2)(x-3)-(x-2)^2)=0\\
(x-1)^2(4(x^2-3x+2x-6)-(x^2-4x+4))=0\\
(x-1)^2(4x^2-4x-24-x^2+4x-4)=0\\
(x-1)^2(3x^2-28)=0\\
x-1=0 \vee 3x^2-28=0\\
x=1 \vee 3x^2=28\\
x=1 \vee x^2=\dfrac{28}{3}\\
x=1 \vee x=\sqrt{\dfrac{28}{3}} \vee x=-\sqrt{\dfrac{28}{3}}\\$

There's one more condition I forgot about
$-(x-2)(x-1)\geq0\\
x\in\langle1,2\rangle\\$

Finally
$x\in(-\infty,-2\rangle\cup\langle3,\infty) \wedge x\in\langle1,2\rangle \wedge x=\{1,\sqrt{\dfrac{28}{3}}, -\sqrt{\dfrac{28}{3}}\}\\
\boxed{\boxed{x=1}}$

3 0

2 years ago

Helen used 1/4 of her savings for her first year of college. 3/8 of that money was spent on her housing and meals. Which equatio

iren [92.7K]

3/32
just multiply the fractions

8 0

3 years ago

Read 2 more answers

Find the measure of the indicated angle.<br> Please can you help?<br> I need to show work.

777dan777 [17]

Answer:

64°

Step-by-step explanation:

∠RQP = 46°

∠PRQ = 180° - 110° = 70°

∠PRQ + ∠RQP + <u>∠RPQ</u> = 180°

70° + 46 + <u>∠RPQ</u> = 180°

116° + <u>∠RPQ</u> = 180°

Find <u>∠RPQ</u>

<u>∠RPQ</u> = 180° - 116° = 64°

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3 years ago

Artyom0805 [142]

Answer:

C) $y = \frac{1}{2}$ × $4^x$

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2 years ago

Read 2 more answers

What is the variable 6w+30+w=4w+90

Vesnalui [34]

<h3><u>The variable is equal to 20.</u></h3>

6w + 30 + w = 4w + 90

Subtract 30 from both sides.

6w + w = 4w + 60

Combine like terms.

7w = 4w + 60

Subtract 4w from both sides.

3w = 60

Divide both sides by 3.

w = 20

6 0

3 years ago