<img src="https://tex.z-dn.net/?f=2%288x%20-%207%29" id="TexFormula1" title="2(8x - 7)" alt="2(8x

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olganol [36]

3 years ago

"latex-formula">
how to do this

Mathematics

2 answers:

natima [27]3 years ago

6 0

This is distributive property and to do distributive property, you distribute what is outside of the parenthesis to the numbers inside the parenthesis.

How-to-do:

2(8x-7)

2(8x) - 2(7)

16x-14

Mariulka [41]3 years ago

5 0

if you mean to simplify :

2(8x−7)

=(2)(8x+−7)

=(2)(8x)+(2)(−7)

=16x−14

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Given f (x) = x2 + 4x + 5, what is f of the quantity 2 plus h end quantity minus f of 2 all over h equal to?

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By evaluating the quadratic function, we will see that the differential quotient is:

$\frac{f(2 + h) - f(2)}{h} = 8 + h$

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So we need to replace the x-variable by "2 + h" and "2" respectively.

Replacing the function in the differential quotient:

$\frac{(2 + h)^2 + 4*(2 + h) + 5 - (2)^2 - 4*2 - 5}{h} \\\\\frac{4 + 2*2h + h^2 + 8 + 4h - 4 - 8 }{h} \\\\\frac{ 2*2h + h^2 + 4h }{h} = \frac{8h + h^2}{h}$