Answer:
If i have three moles of a gas at a pressure of 5.6 atm and a volume of 3 liters, what is the temperature ?
We have the following data:
n (number of moles) = 3 moles
P (pressure) = 5.6 atm
V (volume) = 12 L
T (temperature) = ? (in Kelvin)
R (gas constant) = 0.082 atm.L / mol.K
We apply the data above to the Clapeyron equation (gas equation), let's see:
Answer:
The temperature is approximately 205 Kelvin
Answer:
The improper fraction of 9 1/3 is 28/3
Step-by-step explanation:
solution,
midpoint between A(-1,4) and B(-5,-2)=
(X1 + X2 ÷2, Y1 + Y2 ÷2)
=(-1-5÷2 , 4-2)
=(-6÷2 ,2÷2)
=(-3 , 1)
therefore the midpoint between A(-1,4) and B(-5 ,-2)=(-3,1)
Step-by-step explanation:
m = 14, n = 12.5
m<L = (5m + 36)° = (5(14) + 36)°
L = 106°
m<p= (6n-1°)=(6x12.5-1°)
p=74°
m<Q = (4m + 50)° = (4(14) + 50)°
Q = 106°
k=360°-(106°+74+°106°)=360°-286°
k=74°
The sum of the interior angle of a parallelogram is 360°
The opposite side of a parallelogram are equal.
107° because a line is 180 degrees and 180 minus 73 is 107
