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svetoff [14.1K]
3 years ago
7

Please help! Combine like terms.

Mathematics
1 answer:
Leto [7]3 years ago
6 0

Expand

0.5x^4 - 4.5 + 13

Collect like terms

0.5x^4 + (-4.5 + 13)

Simplify

<u>0.5x^4 + 8.5 </u>

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Y=-x^2-14x-59<br> pls help
Nady [450]
There would be no solution.
3 0
3 years ago
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Solve the inequality<br> 4b−4≤−20
devlian [24]

Answer:

b ≤ -4

Step-by-step explanation:

4b−4≤−20

4b - 4 + 4 ≤ - 20 + 4

4b ≤ -16

Divide both sides by 4

b ≤ -4

8 0
2 years ago
Find dy/dx by implicit differentiation.
kow [346]

dy/dx by implicit differentiation is cos(πx)/sin(πy)

<h3>How to find dy/dx by implicit differentiation?</h3>

Since we have the equation

(sin(πx) + cos(πy)⁸ = 17, to find dy/dx, we differentiate implicitly.

So, [(sin(πx) + cos(πy)⁸ = 17]

d[(sin(πx) + cos(πy)⁸]/dx = d17/dx

d[(sin(πx) + cos(πy)⁸]/dx = 0

Let sin(πx) + cos(πy) = u

So, du⁸/dx = 0

du⁸/du × du/dx = 0

Since,

  • du⁸/du = 8u⁷ and
  • du/dx = d[sin(πx) + cos(πy)]/dx

= dsin(πx)/dx + dcos(πy)/dx

= dsin(πx)/dx + (dcos(πy)/dy × dy/dx)

= πcos(πx) - πsin(πy) × dy/dx

So, du⁸/dx = 0

du⁸/du × du/dx = 0

8u⁷ × [ πcos(πx) - πsin(πy) × dy/dx] = 0

8[(sin(πx) + cos(πy)]⁷ ×  (πcos(πx) - πsin(πy) × dy/dx) = 0

Since 8[(sin(πx) + cos(πy)]⁷ ≠ 0

(πcos(πx) - πsin(πy) × dy/dx) = 0

πcos(πx) = πsin(πy) × dy/dx

dy/dx = πcos(πx)/πsin(πy)

dy/dx = cos(πx)/sin(πy)

So, dy/dx by implicit differentiation is cos(πx)/sin(πy)

Learn more about implicit differentiation here:

brainly.com/question/25081524

#SPJ1

6 0
2 years ago
A square is cut from a rectangle. The side length of the square is half of the unknown width w. The area of the shaded region is
Virty [35]

Answer:

  • See below

Step-by-step explanation:

<u>The side of the square is w/2, then its area is:</u>

  • A = (w/2)² = w²/4

<u>The shaded area is the difference of areas of the rectangle and the square:</u>

  • 14w - w²/4 = 84

<u>This can be simplified:</u>

  • 56w - w² = 336
  • w² - 56w + 336 = 0

8 0
2 years ago
Please help me out with this so I can keep my kitten.
notka56 [123]

Answer:

y = \frac{32}{3}

Step-by-step explanation:

Firstly, move over the negative 3/4 fraction (don't forget to swap the operation i.e subtract to add):

\frac{y}{8} = \frac{7}{12}  + \frac{3}{4}

Now, to add the two fractions, simply multiply the numerator and denominator by 3:

\frac{3*3}{4*3} = \frac{9}{12}

Now add this to the other fraction:

\frac{9}{12} + \frac{7}{12} = \frac{16}{12}

This can be simplified down by dividing both the numerator and denominator by 4:

\frac{4}{3}

Which now simplifies the original equation to:

\frac{y}{8}  = \frac{4}{3}

Remove the y out of the fraction:

\frac{1}{8}y = \frac{4}{3}

Now multiply both sides by 8:

(\frac{1}{8}y) * 8 = (\frac{4}{3}) * 8

y = \frac{4*8}{3}

y = \frac{32}{3}

Hope this helps!

5 0
3 years ago
Read 2 more answers
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