Answer:
the 2nd graph
*this is my first time answering a question xd*
<span>Just list all elements that belong both to A and to B
A ∩ B = {6,12}</span>
Answer:
Width = 12 in
Length = 16 in
Step-by-step explanation:
Let, the Width of the rectangle = w in
Now, the length of the rectangle = (w + 4) in
Now, Perimeter = 56 in
Also, we know that
Perimeter of the Rectangle = 2 (Length +Width)
or, 2 (Length +Width) = 56
⇒ 2(w + 4 +w) = 56
or, 4w =56 -8
width = 12 in
So, Length = w + 4 = 12 + 4 = 16 in
Answer: Ix - 5I ≥ 5.
Step-by-step explanation:
We want the set:
[0, 10]
to be the solution of:
Ix - bI ≤ c
So we need to find the values of c and b.
The first step is to find the middle point in our segment.
We can do that by adding the extremes and dividing it by 2.
M = (10 + 0)/2 = 5
And we also want to find half of the difference between the extremes, this is:
D = (10 - 0)/2 = 5.
Now, this set will be the set of solutions of:
Ix - MI ≥ D
Then in our case, we have:
Ix - 5I ≥ 5.
so we have that b = 5, and c = 5.
Answer:
7(b^2 -2)(b^2 +2)
Step-by-step explanation:
Factoring the common factor 7 from both terms, you get the difference of squares. That can also be factored.
v = 7(b^4 -4) = 7(b^2 -2)(b^2 +2)
The difference b^2-2 will have irrational factors, so does not meet the problem requirements. This is the factorization over integers.
