Answer/Step-by-step explanation:
1. B = 180 - (90 + 58) (sum of triangles)
B = 32°
Let's find a and b using trigonometric ratios:
Reference angle = 58°
Opposite = a = ?
Hypotenuse = c = 27
Adjacent = b = ?
✔️To find a, apply SOH:
Sin 58 = Opp/Hyp
Sin 58 = a/27
a = 27*Sin 58
a = 22.8972986 ≈ 22.9 (nearest tenth)
✔️To find b, apply CAH:
Cos 58 = Adj/Hyp
Cos 58 = b/27
b = 27*Cos58
b = 14.3 (nearest tenth)
2. B = 180 - (90 + 63) (sum of triangles)
B = 27°
Let's find a and b using trigonometric ratios:
Reference angle = 63°
Opposite = a = 11
Hypotenuse = c = ?
Adjacent = b = ?
✔️To find b, apply TOA:
Tan 63 = Opp/Adj
Tan 63 = 11/b
b = 11/Tan 63
b = 5.6 (nearest tenth)
✔️To find c, apply SOH:
Sin 63 = Opp/Hyp
Sin 63 = 11/c
c = 11/Sin 63
c = 12.3 (nearest tenth)
First ABC is reflected across the y axis to become A'B'C'
Then A'B'C' is rotated 90 counterclockwise about the origin to make it A"B"C"
Because the transformations are both rigid, the pre-image and image are congruent
Hope this helped
Answer:
0.007 × 10 = 0.07
Step-by-step explanation:
cant do step by step
Answer:
-10y + 10.5
Step-by-step explanation:
5 - 2y + (-8y) + 5.5
5 - 2y - 8y +5.5
-10y + 10.5
