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steposvetlana [31]
3 years ago
12

How do u write twenty-seven hundreths

Mathematics
2 answers:
LenKa [72]3 years ago
5 0
27,000 that's how you write it I guess
erma4kov [3.2K]3 years ago
3 0
0.27 would be the answer

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Twenty six equals eight plus v
Mumz [18]

18. You can do this in a calculator. 26 - 8 = 18. v = 18.

6 0
4 years ago
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PLEASE HELP ASAP!! ONLY IF YOU KNOW THE ANSWER! THANK YOU SO MUCH!
telo118 [61]

Answer:

f(x)=-x

I hope this helps :)

8 0
3 years ago
If b = 5, what is b to the square root of 3
liubo4ka [24]
Is 125 because u need to take the 5 and add 3 on the top

6 0
3 years ago
Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu
Alisiya [41]
Let y=C_1x+C_2x^3=C_1y_1+C_2y_2. Then y_1 and y_2 are two fundamental, linearly independent solution that satisfy

f(x,y_1,{y_1}',{y_1}'')=0
f(x,y_2,{y_2}',{y_2}'')=0

Note that {y_1}'=1, so that x{y_1}'-y_1=0. Adding y'' doesn't change this, since {y_1}''=0.

So if we suppose

f(x,y,y',y'')=y''+xy'-y=0

then substituting y=y_2 would give

6x+x(3x^2)-x^3=6x+2x^3\neq0

To make sure everything cancels out, multiply the second degree term by -\dfrac{x^2}3, so that

f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y

Then if y=y_1+y_2, we get

-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0

as desired. So one possible ODE would be

-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0

(See "Euler-Cauchy equation" for more info)
6 0
4 years ago
each student in ms sikes's kindergarten class has a box of crayons. each box has 36 crayons.if there are 18 students in ms sikes
UkoKoshka [18]
The answer is 648.

You have to multiply 36 by 18 to get 648

36×18 = 648

Hope that Helps :]
3 0
3 years ago
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