Ok so if a man walks 2 ft per second you would want to find out how many seconds it takes to walk 1 foot so it takes .5 seconds to walk one foot so then you multiply 4320X.5 which then equals 2169 seconds then divide that by 60 which equals 36min.
Attached the solution and step by step work.
Answer:
e < 24 is the inequality which shows the possible earnings per share.
Explanation:
x, will stand for the variable for earnings and less than, means it will not be higher nor the same as 24. Thus, being leaves us with one sign. The open part facing 24 means that 24 is the bigger number, therefore the smaller side represents that x has to be smaller than 24.
Answer:
Step-by-step explanation:
line graph- the decrease of attendance
bar graph-the number of students who participate in different sports
line plot-the list of heights of a group of 80 adults
steam and leaf plot- the number of dogs for students
Answer:
32.3
Step-by-step explanation:
First we want to make a triangle like on the left side, so make a new point on AD that is directly below C, we'll call this E.
We know CE is 6 because it's the same as that line going down from B, let me know if you do not see that.
now we want to find the last leg of this new triangle CED, the non hypotenuse. We know AD is 24 CM. It is now sebarated into three parts, the beginning part in the left most triangle, the 10 cm between the triangles and the side we want to find. Since we know the middle part we want to find the left part.
The left part of AD can be found with the pythagorean theorem.
this can be turned into
Now we know 24 = 10 + 4.5 + y, with y being the right part. So now we know y=9.5
Back to the new triangle, we know two sides and want to find an angle, so we can do some inverse trig functions. Relatie to the angle we want to find we have the opposite (6) and the adjacent (9.5) so we use tangent. tan(theta)= o/a = 6/9.5. Using the inverse of tangent or arctan (because it's easier to type) arctan(6/9.5)=32.276 which rounds to 32.3. Again, let me know if you need help with any of this.