* please help 20 points !! *<br> which statement can be proved if you are given that SK≌LR?

Write in word form 300+10+2

sineoko [7]

Answer:

Three hundred plus ten plus two equals three hundred twenty two

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

How to graph the linear function: <br> g(x) = -4 + 7x

hjlf

Answer:

Step-by-step explanation:

Slope: 7/1

y-intercept: (0,-4)

Start in the y-intercept (0,-4). Go up 7 and 1 to the right. You only need two points to trace a line.

8 0

3 years ago

The probability that your call to a service line is answered in less than 30 seconds is 0.75. Assume that your calls are indepen

vfiekz [6]

Answer:

a) 0.2581

b) 0.4148

c) 17

Step-by-step explanation:

For each call, there are only two possible outcomes. Either they are answered in less than 30 seconds. Or they are not. The probabilities for each call are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$p = 0.75$

a. If you call 12 times, what is the probability that exactly 9 of your calls are answered within 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X = 9)$ when $n = 12$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{12,9}.(0.75)^{9}.(0.25)^{3} = 0.2581$

b. If you call 20 times, what is the probability that at least 16 calls are answered in less than 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X \geq 16)$ when $n = 20$

So

$P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 16) = C_{20,16}.(0.75)^{16}.(0.25)^{4} = 0.1897$

$P(X = 17) = C_{20,17}.(0.75)^{17}.(0.25)^{3} = 0.1339$

$P(X = 18) = C_{20,18}.(0.75)^{18}.(0.25)^{2} = 0.0669$

$P(X = 19) = C_{20,19}.(0.75)^{19}.(0.25)^{1} = 0.0211$

$P(X = 20) = C_{20,20}.(0.75)^{20}.(0.25)^{0} = 0.0032$

So

$P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.1897 + 0.1339 + 0.0669 + 0.0211 + 0.0032 = 0.4148$

c. If you call 22 times, what is the mean number of calls that are answered in less than 30 seconds? Round your answer to the nearest integer.

The expected value of the binomial distribution is:

$E(X) = np$

In this question, we have $n = 22$

So

$E(X) = 22*0.75 = 16.5$

The closest integer to 16.5 is 17.

7 0

3 years ago

Selesaikan persamaan linear serentak berikut.<br> 2x + y = -5<br> 3x - 4y = 9

makkiz [27]

Answer:

(-1;-3)

Step-by-step explanation:

$\left \{ {{4(2x+y)=4*(-5)} \atop {3x-4y=9}} \right. \ => \ \left \{ {{8x+4y=-20} \atop {3x-4y=9}} \right. \ => \ \left \{ {{11x=-11} \atop {2x+y=-5}} \right. \ => \ \left \{ {{x=-1} \atop {y=-3}} \right.$

8 0

3 years ago

The time t (in minutes) for a small plane to climb to an altitude of h feet is given by t = 50 log10 (18000/(18000-h)) where 180

Arlecino [84]

Domain = x<18000(You cant og a negative number)
Am I actually supposed to graph it? enter the equation on desmos.com
It takes longer to make the same altitudinal gain
t=50log(18000/(18000-4000))=50log(18000/14000)=5.457

5 0

3 years ago

* please help 20 points !! * which statement can be proved if you are given that SK≌LR?