1. X(0,0) --> X'(3,-5).
To go from (0,0) to (3,-5), you must go to the right 3 and down 5.

I cannot answer 2 or 3, as rotations are not my strong suit.

4 0

3 years ago

Read 2 more answers

Please help me with this equation, add process too. Thanks

ICE Princess25 [194]

$\qquad\qquad\huge\underline{\boxed{\sf Answer☂}}$

Let's solve ~ ☂

$\qquad \sf \dashrightarrow \: - 0.6(m + 1) = 3$

$\qquad \sf \dashrightarrow \: - (m + 1) = 3 \div 0.6$

$\qquad \sf \dashrightarrow \: - (m + 1) = 5$

$\qquad \sf \dashrightarrow \: - m - 1= 5$

$\qquad \sf \dashrightarrow \: - m = 5 + 1$

$\qquad \sf \dashrightarrow \: - m = 6$

$\qquad \sf \dashrightarrow \: m = - 6$

I hope it helps ~

6 0

2 years ago

I need with #10, please?

777dan777 [17]

Answer:

h=7ft

Step-by-step explanation:

sinФ=opposite/hypotenuse

sin45°=5/h

0.71=5/h

multiply via by h

0.71h=(5/h)h

h cancel h it remains 5

0.71h=5

divide through by 0.71

0.71h/0.71=5/0.71

h=7.04ft

h=7ft approximately

4 0

3 years ago

The measure of angle P is five less than four times the measure of angle Q. Of angle P and angle Q are supplementary angles, fin

Andru [333]

Answer:

m∠P=140°

Step-by-step explanation:

Given:

∠P and ∠Q are supplementary angles.

The measure of angle P is five less than four times the measure of angle Q.

To find m∠P

Solution:

The measure of angle P can be given as:

A) $m\angle P=4(m\angle Q-5)$

And

B) $m\angle P+ m\angle Q=180$ [Definition of supplementary angles]

Substituting equation A into B.

$4(m\angle Q-5)+ m\angle Q=180$

Solving for $m\angle Q$

Using distribution:

$4m\angle Q-20+ m\angle Q=180$

Simplifying by combining like terms.

$5m\angle Q-20=180$

Adding 20 to both sides.

$5m\angle Q-20+20=180+20$

$5m\angle Q=200$

Dividing both sides by 5.

$\frac{5m\angle Q}{5}=\frac{200}{5}$

$m\angle Q=40$

Substituting $m\angle Q=40$ in equation B.

$m\angle P+ 40=180$

Subtracting both sides by 40.

$m\angle P+ 40-40=180-40$

$m\angle P=140$

Thus, we have:

m∠P=140° (Answer)

7 0

3 years ago