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2 years ago

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How do I solve this?

1 answer:

Korolek [52]2 years ago

6 0

<span><span> (<span>x−8</span>)</span>2</span><span>=<span><span>(<span>x+<span>−8</span></span>)</span><span>(<span>x+<span>−8</span></span>)</span></span></span><span>=<span><span><span><span><span>(x)</span><span>(x)</span></span>+<span><span>(x)</span><span>(<span>−8</span>)</span></span></span>+<span><span>(<span>−8</span>)</span><span>(x)</span></span></span>+<span><span>(<span>−8</span>)</span><span>(<span>−8</span>)</span></span></span></span><span>=<span><span><span><span>x2</span>−<span>8x</span></span>−<span>8x</span></span>+64</span></span><span>=<span><span><span>x2</span>−<span>16x</span></span>+<span>64

</span></span></span><span>(x−8)2=x2−82Step 1: Simplify both sides of the equation.x2−16x+64=x2−64Step 2: Subtract x^2 from both sides.x2−16x+64−x2=x2−64−x2−16x+64=−64Step 3: Subtract 64 from both sides.−16x+64−64=−64−64−16x=−128Step 4: Divide both sides by -16.−16x−16=−128−16x=8</span>

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Coordinates of the point representing the location of Miya → (1, 10)

Coordinates of the point representing the location of Drea → (13, 1)

Coordinates of the point representing the location of Francine → (16, 1)

Coordinates of the point representing the location of Beach → (19, 4)

Distance between Miya and Drea = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

= $\sqrt{(13-1)^2+(1-10)^2}$

= $\sqrt{144+81}$

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Distance between Drea and Francine = $\sqrt{(16-13)^2+(1-1)^2}$

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Distance between Francine and Beach = $\sqrt{(19-16)^2+(4-1)^2}$

= $\sqrt{9+9}$

≈ 4.2 miles

Total distance between Miya and the beach = 15 + 3 + 4.2

= 22.2 miles

Option (C) is the answer.

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