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3 years ago

How do I solve this?

Mathematics

1 answer:

Korolek [52]3 years ago

6 0

(x−8)2=(x+−8)(x+−8)=(x)(x)+(x)(−8)+(−8)(x)+(−8)(−8)=x2−8x−8x+64=x2−16x+64

(x−8)2=x2−82Step 1: Simplify both sides of the equation.x2−16x+64=x2−64Step 2: Subtract x^2 from both sides.x2−16x+64−x2=x2−64−x2−16x+64=−64Step 3: Subtract 64 from both sides.−16x+64−64=−64−64−16x=−128Step 4: Divide both sides by -16.−16x−16=−128−16x=8

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3 years ago

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vova2212 [387]

Answer:

Point-slope form of equation given as $y-2=-2(x+2)$ .

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Step-by-step explanation:

In the question, it is given that the slope of a line is -2 and it passes from (-2,2).

It is asked to write the point-slope form of the equation and rewrite it as slope-intercept form.

To do so, first find the values which are given in the question and put it in the formula of point-slope form. Simplify the equation to rewrite as slope-intercept form.

Step 1 of 2

Passing point of the line is (-2,2).

Hence, $x_{1}=-2$ and

$y_{1}=2 \text {. }$

Also, the slope of the line is -2.

Hence, m=-2

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$\begin{aligned}&y-y_{1}=m\left(x-x_{1}\right) \\&y-2=-2(x-(-2) \\&y-2=-2(x+2)\end{aligned}$

Hence, point-slope form of equation given as y-2=-2(x+2).

Step 2 of 2

Solve y-2=-2(x+2) to write it as slope-intercept form given by y=mx+c.

$\begin{aligned}&y-2=-2(x+2) \\&y-2=-2 x-4 \\&y=-2 x-4+2 \\&y=-2 x-2\end{aligned}$

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2 years ago

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denis-greek [22]

Answer:

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Step-by-step explanation:

Number Permutations

We know the phone number has 7 digits, 4 of which are known by Mark. This leaves him 3 digits to guess with. We also know the last one is not zero. The number can be represented as

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3 years ago

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Vladimir79 [104]

I'm guessing its 1800.

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