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maxonik [38]
3 years ago
9

Y=2x-8.75 what is the initial value​

Mathematics
1 answer:
Alex3 years ago
5 0

Answer:

4.375

Step-by-step explanation:

8.75=2x

/2       /2

4.375=x

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How many 3-digit even numbers are that begin with either 5 or 6?
mojhsa [17]
Answer: 100 3 digit even number that begin with either 5 or 6

Explanation:
Case 1:
A 3 digit that begin with 5 should be 500-599 so there are 100 numbers
But we are only finding even number
So 100/2 = 50 3-digit even number that begin with 5.

Case 2:
A 3 digit that begin 6 should have
600-699 and there are also 100 number including even and odd in total. Since we are only finding even number we get:
100/2 = 50 3-digit even number that begin with 6.

Plus both case together we get 50 3-digit even number that begin with 5 + 50 3-digit even number that begin with 6= 50 + 50 = 100
8 0
3 years ago
Read 2 more answers
When it was built, the given stadium held 31,080 fans per game. Today, it holds 86,047. How many more fans could attend per year
RSB [31]

Answer:

659604 students

Step-by-step explanation:

86047-31080=54967 more students per game

54967 students per game x 12 games = 659,604 students

4 0
3 years ago
Could u give me the answer Bc I need it
QveST [7]

Answer:

what is the question?

Step-by-step explanation:

8 0
3 years ago
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PLSSSS HELPPPPP ASAP
jolli1 [7]
D.

Perimeter is when you add and not multiple:)
6 0
3 years ago
Please Help Me
ludmilkaskok [199]

Given:

The point (9,-12) is on terminal side of angle theta in standard position.

To find:

The exact value of each of the six trigonometric functions of theta.

Solution:

The given point is (9,-12). Here, x-coordinate is positive and y-coordinate is negative. So, the point lies in 4th quadrant and only cos and sec are positive in 4th quadrant.

We know that,

r=\sqrt{x^2+y^2}

r=\sqrt{9^2+(-12)^2}

r=\sqrt{81+144}

r=\sqrt{225}

r=15

Now,

\sin \theta=\dfrac{y}{r}=\dfrac{-12}{15}=-\dfrac{4}{5}

\cos \theta=\dfrac{x}{r}=\dfrac{9}{15}=\dfrac{3}{5}

\tan \theta=\dfrac{y}{x}=\dfrac{-12}{9}=-\dfrac{4}{3}

\cot \theta=\dfrac{1}{\tan \theta}=-\dfrac{3}{4}

\text{cosec} \theta=\dfrac{1}{\sin \theta}=-\dfrac{5}{4}

\sec \theta=\dfrac{1}{\cos \theta}=\dfrac{5}{3}

Therefore, the values of six trigonometric functions of theta are \sin \theta=-\dfrac{4}{5},\cos \theta=\dfrac{3}{5},\tan \theta=-\dfrac{4}{3},\cot \theta=-\dfrac{3}{4},\text{cosec} \theta=-\dfrac{5}{4},\sec \theta=\dfrac{5}{3}.

6 0
3 years ago
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