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Vesnalui [34]
3 years ago
7

What is the area of the parallelogram if each square is 1 square foot?

Mathematics
1 answer:
GenaCL600 [577]3 years ago
8 0
12 ft squared

........
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At these numbers functions: (1, 2), (2, 3), (3, 4), (4, 3)
Leona [35]

Answer:

(Add one then subtract one)

Step-by-step explanation:

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What is the m Show work
Ghella [55]

Answer:

measure of angle A is 80 degree.

Step-by-step explanation:

isosceles triangle will have same base angles

first base angle is 50, and the second will also be 50

3 angles of a triangle will add up to be 180 degree.

A is the vertex angle.

So 50 + 50 + A = 180

100 + A = 180

A = 80.

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3 years ago
What is the answer ?
fomenos

Answer:

19/60 or .317

Step-by-step explanation:

C = 95/300

95/300 = 19/60

19/60 = .317

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2 years ago
I need help with this question ASAP
IgorLugansk [536]

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The answer would be 49 I think hehe

Step-by-step explanation:

7 0
3 years ago
Given the quadratic equation <img src="https://tex.z-dn.net/?f=y%20%3D%202%28x%20-1%29%5E%7B2%7D%20%2B%208" id="TexFormula1" tit
Sunny_sXe [5.5K]

Answer:

Part 1) "a" value is 2

Part 2) The vertex is the point (1,8)

Part 3) The equation of the axis of symmetry is x=1

Part 4) The vertex is a minimum

Part 5) The quadratic equation in standard form is y=2x^{2}-4x+10

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

y=a(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

if a > 0 then the parabola open upward (vertex is a minimum)

if a < 0 then the parabola open downward (vertex is a maximum)

The equation of the axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex

so

x=h

In this problem we have

y=2(x-1)^{2}+8 -----> this is the equation in vertex form of a vertical parabola

The value of a=2

so

a>0 then the parabola open upward (vertex is a minimum)

The vertex is the point (1,8)

so

(h,k)=(1,8)

The equation of the axis of symmetry is x=1

The equation of a vertical parabola in standard form is equal to

y=ax^{2}+bx+c

Convert vertex form in standard form

y=2(x-1)^{2}+8

y=2(x^{2}-2x+1)+8

y=2x^{2}-4x+2+8

y=2x^{2}-4x+10

see the attached figure to better understand the problem

7 0
3 years ago
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