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3 years ago

14

Sam has three identical tennis balls with a diameter of 2.7 inches. Determine the volume of all three tennis balls?

1 answer:

melamori03 [73]3 years ago

3 0

Answer:

They are 30.93 in³ altogether.

Step-by-step explanation: V = 4/3 π r³

r = 2.7/2 = 1.35

π x 1.35 x 1.35 x 4/3 = 10.31 in³

10.31 x 3 = 30.93

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Bonnie runs at an average speed 4 metres per second for 240 seconds.

telo118 [61]

Answer:

960 metres in 240 seconds.

Step-by-step explanation:

this is because they can run 4 metres every second.

the number of seconds they ran multiplied by the length of their run in a second is your answer.

240 x 4 = 960

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2 years ago

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What is the simplified form of the following expression? 2√27+√12-3√3-2√12

LiRa [457]

Answer:

√3

Step-by-step explanation:

The given expression to be simplified is

$2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}$

but

$2 \sqrt{27}=2\sqrt{9 \times 3}=2 \times \sqrt{9}\times \sqrt{3}=2 \times 3 \times\sqrt{3}=6 \sqrt{3}$

$\sqrt{12}=\sqrt{4\times3}= \sqrt{4}\times \sqrt{3}=2\sqrt{3}$

Since √12=2√3,this implies that,

$2\sqrt{12}=2\times2\sqrt{3}=4 \sqrt{3}$

Therefore,

$2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}=6\sqrt{3}+2\sqrt{3}-3 \sqrt{3} -4\sqrt{3}$

$=(6+2-3-4)\sqrt{3}$

$=\sqrt{3}$

The simplified form of ,

$2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}$ is √3

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3 years ago

Sixty people purchase raffle tickets. Three winning tickets are selected at random. If each prize is $3000, in how many differen

Alexus [3.1K]

Answer: $^{60}C_{3}$ ways.

Step-by-step explanation:

$^{n}C_{k}$ is the number of ways in which $k$ distinct objects are selected from a pile of $n$ distinct objects.

In our question,there are a total of $60$ people.

So, $n=60$ .

Given that three are selected at random.

So, $k=3$ .

So,the answer is $^{60}C_{3}$ ways.

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3 years ago

ASAP someone please simply two exponents

zhannawk [14.2K]

Answer:

1.) $m^{15}$

2.) $=\frac{1}{y^{15}}$

Give me a comment if you want the explanation.

1.) $\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0$

$\left(m^3\right)^5=m^{3\cdot \:5}$

$\mathrm{Multiply\:the\:numbers:}\:3\cdot \:5=15$

$=m^{15}$

2.) $\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0$

$\left(y^{-3}\right)^5=y^{-3\cdot \:5}$

$=y^{-3\cdot \:5}$

$=y^{-15}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

$=\frac{1}{y^{15}}$

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3 years ago

HELP WITH BOTH PARTSSSSSSSSS

const2013 [10]

Answer:

Wait... that's my name... whatever, here is the answer XD

Step-by-step explanation:

c+9.75=20.75 is the answer :D

Cost of his ticket is $20.75

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3 years ago

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