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Aloiza [94]
3 years ago
11

Assume that y varies inversely with x. If y=1/3 when x=1/2, find y when x=1/4.

Mathematics
1 answer:
LenKa [72]3 years ago
3 0

Answer:

y = \frac{2}{3}

Step-by-step explanation:

Given that y varies inversely with x then the equation relating them is

y = \frac{k}{x} ← k is the constant of variation

To find k use the condition y = \frac{1}{3} when x = \frac{1}{2} , thus

\frac{1}{3} = \frac{k}{\frac{1}{2} } = 2k ( divide both sides by 2 )

k = \frac{1}{6}

y = \frac{1}{6x} ← equation of variation

When x = \frac{1}{4} , then

y = \frac{1}{6(\frac{1}{4}) } = \frac{1}{\frac{3}{2} } = \frac{2}{3}

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a.  24\sqrt{3}  and 41.6

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Step-by-step explanation:

a.

Considering the left side triangle the blue dotted side is the side "opposite" to the angle given and the side 24 is the side that is "adjacent" to the angle given. The trigonometric ratio tan relates opposite to adjacent. Also, let the blue dotted side be y.

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