Irrational roots occurs with its conjugate.
Therefore, -√3 is also root of the function.
The answer is -√3.
Answer:
80 parrots were purchased.
Step-by-step explanation:
Let the total number of parrots be k.
If 20% (or 20/100 = 1/5) flew away and 5% (5/100 = 1/20) died, the remaining parrots will be k – (¹/₅k + ¹/₂₀k) = k – ¼k = ¾k.
Of the remaining, 45% (or 45/100 = 9/20) were sold, which means the total number of sold parrots will be ¾k × ⁹/₂₀ = ²⁷/₈₀k.
The remaining parrots = ¾k – ²⁷/₈₀k = ³³/₈₀k = 33
k = 33 × ⁸⁰/₃₃ = 80 parrots were purchased.
2r+7+2n+n2
Because I combined the ones with like terms.
12/25 * 100 = 48%
Amount/Whole Amount * 100
Answer:
C. -11,325
Step-by-step explanation:
- To know the answer, is convenient to replace some values of "n" in the sum
![\sum_{(n=1)}^{150}[-1-(n-1)]](https://tex.z-dn.net/?f=%5Csum_%7B%28n%3D1%29%7D%5E%7B150%7D%5B-1-%28n-1%29%5D)
.
- The result would appear after adding up every value of the expression when n=1,2,3.....,150.
- When n=1, the expression takes the value of (-1):
![[-1-(1-1)]= (-1)-0=-1](https://tex.z-dn.net/?f=%5B-1-%281-1%29%5D%3D%20%28-1%29-0%3D-1)
. - When n=2, the expression takes the value of (-2):
![[-1-(2-1)]=-1-1=-2](https://tex.z-dn.net/?f=%5B-1-%282-1%29%5D%3D-1-1%3D-2)
. - Following this way, for every n, we will obtain -n, then, the sum will be:
. This sum can actually be expressed as 
, which is the result of solving the initial expression of the sum 
. - Finally, the sum of n=-1 to n=-150 equals -11,325.
