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Basile [38]
3 years ago
10

Am I right. if not please show me work thx.

Mathematics
2 answers:
Drupady [299]3 years ago
8 0
If you're talking about #3, then the equation would be 10+12.50h=5+15h.
h will equal 2, and the cost for that number of hours would then be $35.

larisa86 [58]3 years ago
8 0
Your output for C should be 15 
Your input for D should be 100

Yup Kittlesbug is right for the third one NICE! 
You might be interested in
Help!!
lutik1710 [3]

theoretical probability is a coin will land on heads 50% of the time

50% of 100 = 50

since it only landed on heads 38 times, this was less than the theoretical probability of 50

5 0
3 years ago
Read 2 more answers
A line passes through the point -8,-3 and has a slope of -3/2. write an equation
fomenos

Answer:

y = -3/2x  - 15

Step-by-step explanation:

Use the slope intercept form  y = mx + b to substitute the slope = -3/2 and the point (-8, -3).

y = mx + b

-3 = -3/2(-8) + b

-3 = 12 + b

-15 = b

y = -3/2x - 15

3 0
2 years ago
Plz help me with this Plzzzz!!!!
MrRissso [65]
In pretty sure it’s D , making each side equal to 6
4 0
3 years ago
Read 2 more answers
PLEASE HELP IMAGE IS BELOW!!
guajiro [1.7K]

Answer:

Number of small boxes shipped = 7

Number of large boxes shipped = 15

Step-by-step explanation:

Let the number of small boxes = s

And the number of large boxes = l

Weight of small box = 25 pound

Weight of the large box = 50 pounds

Total weight of the shipment = 925 pounds

Therefore, equation for the weight of shipment will be,

25s + 50l = 925

s + 2l = 37 ----- (1)

Total number of boxes shipped = 22 boxes

Therefore, equation will be,

s + l = 22 ------(2)

Subtract equation (2) from equation (1)

(s + 2l) - (s + l) = 37 -22

l = 15

From equation (2)

s + 15 = 22

s = 7

Therefore, number of small boxes shipped = 7

Number of large boxes shipped = 15

6 0
3 years ago
A) If the 5th term of an A.P. is double the 7th term, show that the sum of the 17 terms zero.​
gayaneshka [121]

Answer:

see explanation

Step-by-step explanation:

The nth term of an AP is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₅ is double a₇ , then

a₁ + 4d = 2(a₁ + 6d) , that is

a₁ + 4d = 2a₁ + 12d ( subtract a₁ from both sides )

4d = a₁ + 12d ( subtract 12d from both sides )

- 8d = a₁

The sum of n terms of an AP is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ] , substitute values

S_{17} = \frac{17}{2} ( 2(- 8d) + 16d)

     = 8.5(- 16d + 16d)

     = 8.5 × 0

     = 0

5 0
2 years ago
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