I think you should tell her you cannot lie about working with her
Answer and Explanation:
To calculate Big O, go through each line of code and determine O(!), O(n) and return your calculation.
For example,
In O (5 +6n), where 6 5 represent five instances of O(1), and 6 represent the 6 O(n).
We compute the time complexity of the algorithm. We get the result, just an estimation. In given algorithms, run time in milliseconds has been provided, such as in T (1) algorithm process in 512 milliseconds and T(2) algorithms process 8129 milliseconds. But big O notation not measured in milliseconds. Information given is not enough to calculate the big O notation.
Answer:
The answer is "64"
Explanation:
There has been 1 Private Key 1 Public Key for every person. The private key is used for other app messages. All else uses the Public Key to encrypt messages with that user. Those keys are numerically related. Even if you have 5 users, you will be given 5 Personal keys and 5 Public keys.
- All user will have a duplicate of other public keys, which indicates (n*n-1) copies of n public keys on different systems to make sure shared contact between all users, plus n private keys.
- The unique key count is 2n, with n^2 distributed private and public keys on different systems.
- 8 people, where 8 is a number, that is equal to n so,
<u>Answer:</u>
Any formula entered in the excel sheet should begin with “=”. Otherwise excel reads that to be a normal text and it will not process the further to get a “result”.
A formula can be entered either in <em>the cell or in the “formula bar”</em>. Once a formula is entered and an enter key is encountered, the result will be displayed in the <em>cell and connected formula</em> gets displayed in the Formula bar.
When we move the focus over that cell it <em>displays only content and not formula,</em> because formula gets displayed only in the “formula bar”.
Answer:
Following are the step by step algorithms is explain below.
Explanation:
Following are the algorithm for searching shortest distances.
- Firstly, Initialize the array variable distance[] = {INF, INF, ….} as well as distance[s] = 0 in which the variable 's' is the beginning vertex
- Then, you have to develop a topological order of the following vertices.
- So, Do in the following for mostly vertex that is the variable 'u' in the topological order.
Do on the following for mostly contiguous vertex that is 'v' of 'u'
if (dist[v] > dist[u] + weight(u, v))
dist[v] = dist[u] + weight(u, v)
