Answer:
A cell grows to its full size, The cell copies its DNA
have a great weekends, hopefully it was the right answer!
Answer:
There are multiple critical paths
Explanation:
The critical path method (CPM), or critical path analysis (CPA), is an algorithm for scheduling a set of project activities. It is commonly used in conjunction with the program evaluation and review technique (PERT). A critical path is determined by identifying the longest stretch of dependent activities and measuring the time required to complete them from start to finish.
The essential technique for using CPM is to construct a model of the project that includes the following:
- A list of all activities required to complete the project (typically categorized within a work breakdown structure),
- The time (duration) that each activity will take to complete,
- The dependencies between the activities and,
- Logical end points such as milestones or deliverable items.
Using these values, CPM calculates the longest path of planned activities to logical end points or to the end of the project, and the earliest and latest that each activity can start and finish without making the project longer. This process determines which activities are "critical" (i.e., on the longest path) and which have "total float" (i.e., can be delayed without making the project longer).
considering the above function of the cpm analysis because you have multiple path, there is tendency that more than path through the project network will have zero slack values.
I think the answer to this would be true
Answer:
Option D, This PC allows a user to save a presentation on a computer
Explanation:
If one choses the option C, the file will be saved in the folder in which the user is working. Hence, option C is incorrect.
Like wise option A is also incorrect as it will require user to provide a location as option for saving the file
Option B is also incorrect as it will allow the user to save files in the C drive/D drive or one drive
Option D is correct because if the user choses this option file will be saved on the computer.
Hence option D is correct
Answer:
See Explaination
Explanation:
#include <iostream>
#include <string.h>
using namespace std;
char *mixem(char *s1, char *s2);
int main() {
cout << mixem("abc", "123") << endl;
cout << mixem("def", "456") << endl;
return 0;
}
char *mixem(char *s1, char *s2) {
char *result = new char[1 + strlen(s1) + strlen(s2)];
char *p1 = s1;
char *p2 = s2;
char *p = result;
while (*p1 || *p2) {
if (*p1) {
*p = *p1;
p1++;
p++;
}
if (*p2) {
*p = *p2;
p2++;
p++;
}
}
*p = '\0';
return result;
}
