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puteri [66]
3 years ago
11

Every Java statement ends with: * Period Colon Double quote Semicolon

Computers and Technology
2 answers:
Zepler [3.9K]3 years ago
8 0

Answer:

semicolon is the answer

blsea [12.9K]3 years ago
5 0
semi colon i did that test
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How to write a program that prompts the user to input two POSITIVE numbers — a dividend (numerator) and a divisor (denominator).
fomenos

Answer:

num1 = int(input("Numerator: "))

num2 = int(input("Denominator: "))

if num1 < 1 or num2<1:

     print("Input must be greater than 1")

else:

     print("Quotient: "+str(num1//num2))

     print("Remainder: "+str(num1%num2))

Explanation

The next two lines prompts the user for two numbers

<em>num1 = int(input("Numerator: "))</em>

<em>num2 = int(input("Denominator: "))</em>

The following if statement checks if one or both of the inputs is not positive

<em>if num1 < 1 or num2<1:</em>

<em>      print("Input must be greater than 1")-> If yes, the print statement is executed</em>

If otherwise, the quotient and remainder is printed

<em>else:</em>

<em>      print("Quotient: "+str(num1//num2))</em>

<em>      print("Remainder: "+str(num1%num2))</em>

<em />

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3 years ago
There is an interface I that has abstract class AC as its subclass. Class C inherits AC. We know that C delegates to an object o
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Answer:

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What feature is not included in most DTP programs?
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3 years ago
four quantum numbers that could represent the last electron added (using the Aufbau principle) to the Argon atom. A n = 2, l =0,
marshall27 [118]

Answer:

  • n = 3
  • l  = 1
  • m_l = 1
  • m_s=+1/2

Explanation:

Argon atom has atomic number 18. Then, it has 18 protons and 18 electrons.

To determine the quantum numbers you must do the electron configuration.

Aufbau's principle is a mnemonic rule to remember the rank of the orbitals in increasing order of energy.

The rank of energy is:

1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d < 6p < 7s < 5f < 6d < 7d

You must fill the orbitals in order until you have 18 electrons:

  • 1s² 2s² 2p⁶ 3s² 3p⁶   : 2 + 2 + 6 + 2 + 6 = 18 electrons.

The last electron is in the 3p orbital.

The quantum numbers associated with the 3p orbitals are:

  • n = 3

  • l = 1 (orbitals s correspond to l = 0, orbitals p correspond to l  = 1, orbitals d, correspond to l  = 2 , and orbitals f correspond to  l = 3)

  • m_l can be -1, 0, or 1 (from - l  to + l )

  • the fourth quantum number, the spin can be +1/2 or -1/2

Thus, the six possibilities for the last six electrons are:

  • (3, 1, -1 +1/2)
  • (3, 1, -1, -1/2)
  • (3, 1, 0, +1/2)
  • (3, 1, 0, -1/2)
  • (3, 1, 1, +1/2)
  • (3, 1, 1, -1/2)

Hence, the correct choice is:

  • n = 3
  • l  = 1
  • m_l = 1
  • m_s=+1/2
5 0
3 years ago
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