3 years ago

Every Java statement ends with: * Period Colon Double quote Semicolon

Computers and Technology

2 answers:

Zepler [3.9K]3 years ago

8 0

Answer:

semicolon is the answer

blsea [12.9K]3 years ago

5 0

semi colon i did that test

You might be interested in

Rainbow six siege imi da ecran negru.Ce sa fac?

Oduvanchick [21]

Mmmmmmmm check the internet

7 0

3 years ago

Which functions can you use to find the square root of a number, and to find the current date, respectively?

JulsSmile [24]

1. A. the SQRT is the squareroot. 2. may be C. Today but I've never heard of a function that returns the date!

8 0

3 years ago

Read 2 more answers

Select the correct answer.

Phoenix [80]

Data availability is the one related to the server being down.

4 0

3 years ago

BitTorrent is software that is commonly used to share audio and video files and documents over the Internet. These files are loc

bearhunter [10]

Router, just know the internet is bunch of routers communicating with each other so the answer is a router

7 0

3 years ago

How long does it take to send a 8 MiB file from Host A to Host B over a circuit-switched network, assuming: Total link transmiss

levacccp [35]

Answer:

Given values are:

$File size= 8 MiB$

$Total Link Transmission Rate = 44.2 Gbps$

$Users = 10$

$Setup Time=85.1 ms$

We know that

1 MiB = $2^{20}$ = 1048576 bytes

1 MiB = $2^{20}$ x8= 8388608 bits

8MiB= 8388608x8 = 67108864 bits

So,

Total Number of bits = 67108864 bits

Now

Total link transmission rate = 44.2 Gbps

1 Gbps = 1000000000 bps

44.2 Gbps = 44.2 x 1000000000 =44200000000 bps

For FDM Network

Transmission rate for one time slot = $\frac{44200,000,000}{10}$ bits per second

Transmission rate for one time slot = 4420000000 bit per second

Transmission rate for one time slot = $\frac{44200,000,000}{10^{3} .10 }$

in milliseconds

Transmission rate for one time slot in =4420000 bits per millisecond

Now,

Total time taken to transmit 8 MiB of file = $\frac{Total Number of Bits}{Transmission Rate}$

Total time taken to transmit 8 MiB of file = $\frac{67108864}{4420000}$

As setup time is also given So,

Total time = Setup time + Transmission Time

Total time = 85.1 + 15.18

Total time = 100.2 milliseconds

Hence it is the time required to send a 8MiB of file from Host A to Host B.

I hope it will hep you!

6 0

3 years ago