1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
uranmaximum [27]
3 years ago
13

Solve for x using trigonometric ratios 10 and 11 please

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
5 0
I’m on the same question I need help to???
You might be interested in
Point-Slope Form<br> *See photo*
Ne4ueva [31]

Answer:

y = 3x - 5

Step-by-step explanation:

We know that the equation 'y = 3x + ?' intersects the point (1, -2). This means that when x = 1, y = -2 in out equation above. To solve this just plug in the x and y values to get '?'.

y = 3x + ?\\-2 = 3(1) + ?\\-5 = ?

Now that we know '?' is -5, we write it back into slope intercept form, so our final answer is y = 3x - 5

4 0
2 years ago
Helllllllpppppppppppppppp
Law Incorporation [45]

Answer:

50x50=1000000

Step-by-step explanation:

4 0
3 years ago
1. (5pts) Find the derivatives of the function using the definition of derivative.
andreyandreev [35.5K]

2.8.1

f(x) = \dfrac4{\sqrt{3-x}}

By definition of the derivative,

f'(x) = \displaystyle \lim_{h\to0} \frac{f(x+h)-f(x)}{h}

We have

f(x+h) = \dfrac4{\sqrt{3-(x+h)}}

and

f(x+h)-f(x) = \dfrac4{\sqrt{3-(x+h)}} - \dfrac4{\sqrt{3-x}}

Combine these fractions into one with a common denominator:

f(x+h)-f(x) = \dfrac{4\sqrt{3-x} - 4\sqrt{3-(x+h)}}{\sqrt{3-x}\sqrt{3-(x+h)}}

Rationalize the numerator by multiplying uniformly by the conjugate of the numerator, and simplify the result:

f(x+h) - f(x) = \dfrac{\left(4\sqrt{3-x} - 4\sqrt{3-(x+h)}\right)\left(4\sqrt{3-x} + 4\sqrt{3-(x+h)}\right)}{\sqrt{3-x}\sqrt{3-(x+h)}\left(4\sqrt{3-x} + 4\sqrt{3-(x+h)}\right)} \\\\ f(x+h) - f(x) = \dfrac{\left(4\sqrt{3-x}\right)^2 - \left(4\sqrt{3-(x+h)}\right)^2}{\sqrt{3-x}\sqrt{3-(x+h)}\left(4\sqrt{3-x} + 4\sqrt{3-(x+h)}\right)} \\\\ f(x+h) - f(x) = \dfrac{16(3-x) - 16(3-(x+h))}{\sqrt{3-x}\sqrt{3-(x+h)}\left(4\sqrt{3-x} + 4\sqrt{3-(x+h)}\right)} \\\\ f(x+h) - f(x) = \dfrac{16h}{\sqrt{3-x}\sqrt{3-(x+h)}\left(4\sqrt{3-x} + 4\sqrt{3-(x+h)}\right)}

Now divide this by <em>h</em> and take the limit as <em>h</em> approaches 0 :

\dfrac{f(x+h)-f(x)}h = \dfrac{16}{\sqrt{3-x}\sqrt{3-(x+h)}\left(4\sqrt{3-x} + 4\sqrt{3-(x+h)}\right)} \\\\ \displaystyle \lim_{h\to0}\frac{f(x+h)-f(x)}h = \dfrac{16}{\sqrt{3-x}\sqrt{3-x}\left(4\sqrt{3-x} + 4\sqrt{3-x}\right)} \\\\ \implies f'(x) = \dfrac{16}{4\left(\sqrt{3-x}\right)^3} = \boxed{\dfrac4{(3-x)^{3/2}}}

3.1.1.

f(x) = 4x^5 - \dfrac1{4x^2} + \sqrt[3]{x} - \pi^2 + 10e^3

Differentiate one term at a time:

• power rule

\left(4x^5\right)' = 4\left(x^5\right)' = 4\cdot5x^4 = 20x^4

\left(\dfrac1{4x^2}\right)' = \dfrac14\left(x^{-2}\right)' = \dfrac14\cdot-2x^{-3} = -\dfrac1{2x^3}

\left(\sqrt[3]{x}\right)' = \left(x^{1/3}\right)' = \dfrac13 x^{-2/3} = \dfrac1{3x^{2/3}}

The last two terms are constant, so their derivatives are both zero.

So you end up with

f'(x) = \boxed{20x^4 + \dfrac1{2x^3} + \dfrac1{3x^{2/3}}}

8 0
2 years ago
What are the coordinates of the vertex of the function below write your answer in the form y-9= -6(x-1)^2
Oliga [24]

Answer:

The co-ordinates of the vertex of the function y-9= -6(x-1)^2 is (1, 9)

<u>Solution:</u>

Given, equation is y-9=-6(x-1)^{2}

We have to find the vertex of the given equation.

When we observe the equation, it is a parabolic equation,

We know that, general form of a parabolic equation is  y-9=-6(x-1)^{2}

Where, h and k are x, y co ordinates of the vertex of the parabola.

\text { Now, parabola equation is } y-9=-6(x-1)^{2} \rightarrow y=-6(x-1)^{2}+9

By comparing the above equation with general form of the parabola, we can conclude that,

a = -6, h = 1 and k = 9

Hence, the vertex of the parabola is (1, 9).

7 0
3 years ago
Solve for each variable​
scZoUnD [109]
How did you get to put a picture
7 0
3 years ago
Other questions:
  • What is the degree of 7x^5+6x^3+4x+2
    7·1 answer
  • The Earth's circumference measured at the equator is approximately 1.3148 × 108 feet. What is the number written in standard for
    5·1 answer
  • determinar el centro y el radio de la circuferencia completando los trinomio cuadrado perfecto x2 + y2 +64x -6y +64
    11·1 answer
  • Justify each step of this inequality by stating the property that was used to get to each step. Given: -5(r+3)&lt;12-10r+3r Prop
    9·1 answer
  • What’s is the next number? <br> 2,3,5,7,11,13,17
    10·1 answer
  • Which statements comparing the function are true?select three options.​
    13·1 answer
  • What is the surface area of the cube?
    6·1 answer
  • What is the slope of line a? <br><br>​
    14·1 answer
  • - The Fun Guys game rental store charges an annual fee of $5 plus $5.50 per game rented. The Game Bank charges an annual fee of
    5·1 answer
  • Which postulate or theorem proves that △ABC and △EDC are congruent?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!