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3 years ago

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Find a formula for the distance from the point P(x,y,z) to each of the following planes. a. Find the distance from P(x,y,z) to

the xy-plane. b. Find the distance from P(x,y,z) to the yz-plane. c. Find the distance from P(x,y,z) to the xz-plane

1 answer:

BARSIC [14]3 years ago

7 0

Answer:

Distance to the xy-plane = |z|

Distance to the yz-plane = |x|

Distance to the xz-plane = |y|

Step-by-step explanation:

The distance from P(x,y,z) to the xy-plane is by definition the magnitude of the vector that goes from the perpendicular projection of P over the xy-plane to the point P, which is exactly the magnitude of the vector (0,0,z) = |z| the absolute value of z

Similarly, the distance from P to the yz-plane is |x| and the distance from P to the xz-plane is |y|

Distance to the xy-plane = |z|

Distance to the yz-plane = |x|

Distance to the xz-plane = |y|

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3 years ago

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3 years ago

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Romashka [77]

Answer:

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Step-by-step explanation:

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2 years ago

The National Safety Council publishes information about automobile accidents in Accident Facts. According to that document, the

vladimir1956 [14]

Answer:

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Binomial probability distribution

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In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

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3 years ago

Help please i need help asap

hram777 [196]

What do you need help with? you have nothing here to answer

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3 years ago