This is the concept of volume of solid materials. Volume is of a rectangular prism is given by:
volume=length*width*height
length=6 units
width=3 units
height=4 units
thus;
volume=6*3*4=72 cubic units
we know that
For the function shown on the graph
The domain is the interval--------> (-∞,0]

All real numbers less than or equal to zero
The range is the interval--------> [0,∞)

All real numbers greater than or equal to zero
so
Statements
<u>case A)</u> The range of the graph is all real numbers less than or equal to 
The statement is False
Because the range is all numbers greater than or equal to zero
<u>case B)</u> The domain of the graph is all real numbers less than or equal to 
The statement is True
See the procedure
<u>case C)</u> The domain and range of the graph are the same
The statement is False
Because the domain is all real numbers less than or equal to zero and the range is is all numbers greater than or equal to zero
<u>case D)</u> The range of the graph is all real numbers
The statement is False
Because the range is all numbers greater than or equal to zero
therefore
<u>the answer is</u>
The domain of the graph is all real numbers less than or equal to 
Answer
19?
Step-by-step explanation:
Answer:
x=36
Step-by-step explanation:
The 2 angles, ∠EAF and ∠FAB are on a straight line. This means they are supplementary, and add to 180 degrees.
So,
∠EAF +∠FAB =180
We know that ∠EAF is 3x and ∠FAB is 2x, so we can substitute them in
3x+2x=180
Combine like terms
5x=180
Divide by 5 on both sides
x=36
So, x=36 degrees, or the last choice
Let r represent the radius of cylinder.
We have been given that the height of a right circular cylinder is 1.5 times the radius of the base. So the height of the cylinder would be
.
We will use lateral surface area of pyramid to solve our given problem.
, where,
LSA = Lateral surface area of pyramid,
r = Radius,
h = height.
Upon substituting our given values in above formula, we will get:
Now we will find the total surface area of cylinder.







Therefore, the ratio of total surface area to lateral surface area is
.