jon's car can travel an average of 35 miles per gallon. How many gallons will he need for a trip of 656 miles?

Mathematics

1 answer:

I am Lyosha [343]3 years ago

3 0

Answer:

19 gallons

Step-by-step explanation:

We divide the total distance by the distance per gallon: 656/35. We get 18.74..., so Jon would need 19 gallons to travel 656 miles.

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A standard coffee mug has a capacity of 16 fluid ounces. If Annie needs to fill 26 mugs with coffee, how many total quarts of co

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First let's find how many total ounces it would be by multiplying 16 ounces by the number of mugs (26).

16 × 26 = 416

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416 ÷ 32 = 13 quarts

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Is there supposed to be a fraction on the 4??

Step-by-step explanation:

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3 years ago

Read 2 more answers

Can someone please explain to me how to get this answer?

SIZIF [17.4K]

Answers:
A = 120
b = 45.0
c = 33.2

Side Note: only one triangle is possible
See attached for a visual. I used GeoGebra to draw the triangle.

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Explanation:

We are given the following information
B = 35
C = 25
a = 68

We need to find the following
A, b, c

where the lower case letters represent the side lengths; the upper case letters are the angles. The angles are opposite their corresponding sides. For instance, side lowercase b is opposite angle uppercase B. The other letters are positioned the same way.

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First use the idea that for any triangle, the three angles (A,B,C) must add to 180 degrees
A+B+C = 180
Replace B and C with 35 and 25. Solve for angle A
A+35+25 = 180
A+60 = 180
A+60-60 = 180-60
A = 120

Now that we know the three angles A = 120, B = 35, C = 25, we can find the missing sides 'b' and 'c'

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We will use the law of sines to find side b
sin(A)/a = sin(B)/b
sin(120)/68 = sin(35)/b
b*sin(120) = 68*sin(35) <<--- cross multiply
b = 68*sin(35)/sin(120)
b = 45.037013350222 <<--- use a calculator; this value is approximate
b = 45.0 <<--- round to the nearest tenth

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Do the same for side c
sin(A)/a = sin(C)/c
sin(120)/68 = sin(25)/c
c*sin(120) = 68*sin(25) <<--- cross multiply
c = 68*sin(25)/sin(120)
c = 33.1838323365404 <<--- use a calculator; this value is approximate
c = 33.2 <<--- round to the nearest tenth