Answer:
(0,-5)
Step-by-step explanation:
Melinda:13/20 miles
Clayton: 5/8 miles
We need to find a LCM
40
Melinda: 26/40
Clayton: 25/40
Melinda goes farther by 1/40 of a mile.
The freight train speed = 22 mph
The passenger train speed = 28 mph
Step-by-step explanation:
Assign the speed of the freight train as; <em>x </em>mph
Since the passenger train travels 6 mph faster than the freight train, its speed will be; (<em>x + 6</em>) mph
In 2 hours, the freight and passenger trains will have traveled (distance = speed * time);
2<em>x</em> and 2(<em>x + 6</em>) miles respectively
Both add up to 100 miles. Therefore;
2x + 2(x +6) = 100
4x + 12 = 100
4x = 88
x = 22
x + 6 = 28
The freight train speed = 22 mph
The passenger train speed = 28 mph
Answer:
Your answer is: 19k - 7
Simplify the expression.
Step-by-step explanation:
Hope this helped : )
There were an on-time departure for all 3 flights in 5 of the simulations.