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Vaselesa [24]
3 years ago
14

Se tiene 2 metros de tela y se corta el 85% para hacer cortinas el 50% del resto para hacer las tiras que la sujetan.¿cuantos se

ntimetros de tela quedaron?
Mathematics
1 answer:
zavuch27 [327]3 years ago
3 0

For this case we have the following statement:

<em>"You have 2 meters of fabric and you cut 85% to make curtains, 50% of the rest to make the strips that hold it. How many centimeters of fabric were left?"</em>

So, we have:

2 meters ---------> 100%

x ----------------------> 85%

Where "x" represents the amount of fabric meters equivalent to 85%.

x = \frac {85 * 2} {100}\\x = 1.7

Thus, 1.7 meters of fabric were used to make curtains.

There are 0.3 meters of fabric left, of which half (50%) is used to make the strips that hold the curtain. That is to say:

\frac {0.3} {2} = 0.15m

Thus, 0.15 meters of fabric remain.

0.15 m * \frac {100 cm} {1 m} = 15\ centimeters.

Thus, 15 cm of fabric remain

Answer;

15 cm

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What set does 30 belong to
docker41 [41]

Answer:

30 belongs to the set of real numbers, the set of rational numbers, the set of whole numbers, the set of natural numbers and the set of integers.

Step-by-step explanation:

7 0
3 years ago
What is the next number in the sequence? 3, 6, 12, , ... place an x by the pattern of the sequence. add 2 subtract 2 times 2?
ch4aika [34]
3,6,12...

this is a geometric sequence with a common ratio of 2. That means u multiply each term by 2 to find the next term.

start with 3
3 * 2 = 6
6 * 2 = 12
12 * 2 = 24...this would be ur next term

so ur answer is : multiply by 2
8 0
3 years ago
Which two integers are 7 units away from the number 5 on a number line? A-2 and 2 O B-2 and c. -- and D. -2 and​
Sloan [31]

Answer:

-2 and 12

Step-by-step explanation:

To find the two numbers which are 7 units away from 5, add 7 to 5 and subtract 7 from 5

5+7 = 12

5-7 = -2

5 0
2 years ago
Calcula y comprueba las ecuaciones: porfavor alguienn la nesesito pliss a) 2X = 6 b) 10 + Z = 20 c) P + 9 = 11 d) 3X + 8 = + 29
Alexeev081 [22]

Answer:

<u>a) x = 3</u>

<u>b) z = 10</u>

<u>c) p = 2</u>

<u>d) x = 7</u>

<u>e) u = 1</u>

Step-by-step explanation:

a) 2x = 6

Despejamos x dividiendo por 2 a amabos lados de la eacuacion.

(2/2)x = 6/2

<u>x = 3</u>

Si remplazamos x en la ecuación original:

2(3)=6

6 = 6

Queda demostrado.

b) 10 + z = 20

Despejamos z restando 10 en amabos lados de la eacuacion.

10-10+z = 20-10

<u>z = 10</u>

Si remplazamos z en la ecuación original:

10 + 10=20

20 = 20

Queda demostrado.

c) p + 9 = 11

Despejamos p restando 9 en amabos lados de la eacuacion.

p + 9 - 9 = 11-9

<u>p = 2</u>

Si remplazamos p en la ecuación original:

2 + 9 = 11

11 = 11

Queda demostrado.

d) 3x + 8 = 29

Despejamos x restando 8 en amabos lados de la eacuacion y luego divideindo por 3 en ambos lados de la ecuación.

3x+8-8 = 29-8

3x = 21

(3/3)x = 21/3

<u>x = 7</u>

Si remplazamos x en la ecuación original:

3(7) + 8 = 29

21 + 8 = 29

29 = 29

Queda demostrado

e) 2u + 8 = 10

Despejamos u restando 8 en amabos lados de la eacuacion y luego divideindo por 2 en ambos lados de la ecuación.

2u+8-8 = 10-8

2x = 2

(2/2)x = 2/2

<u>x = 1</u>

Si remplazamos x en la ecuación original:

2(1) + 8 = 10

2 + 8 = 10

10 = 10

Queda demostrado

Espero te haya sido de ayuda!

5 0
2 years ago
2 poi
jolli1 [7]

Me ayudas por favor es regla de ruffini apretá mi perfil y ve mi pregunta

7 0
3 years ago
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