Answer:
Epic username: AspectLegends
Explanation:
Answer:
d
Explanation:
The one action listed in the question that would suggest unfair labor practices would be if Hyper-Tech managers prohibited the distribution of union literature in the company cafeteria. This is because a company can prevent employees from partaking in other tasks and getting distracted while on duty. When an employee is on duty they are getting paid to focus and complete their responsibilities. An employer also has the right to prevent non-employee individuals from entering private property such as their facility. What a company cannot do is prevent their employees from deciding what the literature that they want to read or the decisions that they want to make outside of work hours. Therefore, preventing the employees from accepting literature while on their break time would be considered unfair labor practice.
Answer:
1. Hydrostatic pressure.
2. Pressure.
3. Equilibrium forces.
Explanation:
1. <u>Hydrostatic pressure</u>: pressure exerted by a stationary liquid. It is simply the pressure in a liquid such as water at a specific depth.
Mathematically, hydrostatic pressure is given by the formula;
Where:
- H.P is the hydrostatic pressure of a liquid.
- rho represents the density of a liquid.
- g is the acceleration due to gravity.
- d is the depth (height) of a liquid.
2. <u>Pressure</u>: it is the force in a direction perpendicular to a given surface area. Thus, it's typically measured in Newton per meters (N/m²).
Mathematically, pressure is given by the formula;
3. <u>Equilibrium forces</u>: a pair of forces whose resultant is zero. It is also referred to as balanced forces because the resultant of all the pair of forces acting on a body or system is at equilibrium (balanced).
Answer:
// program in C++.
#include <bits/stdc++.h>
using namespace std;
int main() {
// variable
int num;
cout<<"Enter the number between 20 and 98: ";
// read number
cin >> num;
while(num<20||num>98)
{
cout<<"Wrong input!!enter number between 20-98 only:";
cin>>num;
}
cout<<"The output is: ";
while(num % 10 != num /10)
{
// print numbers.
cout<<num<<" ";
// update num.
num--;
}
// display the number.
cout<<num<<endl;;
return 0;
}
Explanation:
Read a number from user and assign it to variable "num".Check if entered number is in between 20-98 or not.If input number is less than 20 or greater than 98 then ask again to enter a number between 20-98 until user enter a valid input.Then print the countdown from input number till both the digit of number are same.
Output:
Enter the number between 20 and 98: 99
Wrong input!!enter number between 20-98 only:12
Wrong input!!enter number between 20-98 only:93
The output is: 93 92 91 90 89 88
Enter the number between 20 and 98: 77
The output is: 77
