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Goryan [66]
3 years ago
14

The ____ criteria filter requires the records displayed to start with the specified text string

Computers and Technology
1 answer:
lys-0071 [83]3 years ago
3 0

The "Begins With" criteria filter is what your looking for

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What are the first and the last physical memory addressesaccessible using
Misha Larkins [42]

Answer

For First physical memory address,we add 00000 in segment values.

For Last physical memory address,we add 0FFFF in segment values.

<u>NOTE</u>-For addition of hexadecimal numbers ,you first have to convert it into binary then add them,after this convert back it in hexadecimal.

a)1000

For First physical memory address, we add 00000 in segment value

We add 0 at the least significant bit while calculating.

          1000<u>0</u> +00000 = 1000<u>0</u> (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           1000<u>0</u> +0FFFF =1FFFF    (from note)

b)0FFF

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

     0FFF<u>0</u> +00000=0FFF0 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           0FFF<u>0</u> +0FFFF =1FFEF (from note)

c)0001

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

     0001<u>0</u> +00000=00010 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           0001<u>0</u> +0FFFF =1000F (from note)

d) E000

For First physical memory address,we add 00000 in segment value

 We add 0 at the least significant bit while calculating.

    E000<u>0</u> +00000=E0000 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           E000<u>0</u> +0FFFF =EFFFF (from note)

e) 1002

For First physical memory address,we add 00000 in segment value

 We add 0 at the least significant bit while calculating.

    1002<u>0</u> +00000=10020  (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           1002<u>0</u> +0FFFF =2001F (from note)

6 0
2 years ago
Where can we buy a cryptocurrency? from below options
dem82 [27]

it would be C

hope this helps!

8 0
2 years ago
Teenagers and their parents will never understand each other-the generation gap is too big. Its for my grade 11 English speech​
bazaltina [42]

Answer:

lol

Explanation:

lol

7 0
2 years ago
Read 2 more answers
Some of the users in your company create and delete so many files that they have problems with fragmented disks. Which of the fo
zavuch27 [327]

Answer:

D) extents

Explanation:

Disks fragmentations in computer science refers to the cases of a file system laying out its contents  in a non-continuous manner thus preventing an in-place alteration of the contents (that is the contents of the file are scattered in fragments across different location on the disk). Disk fragmentation is mostly associated with aging. To mitigate against this, modern implementation of file systems try to preallocate longer chunks of disk space, this is called extents, in this way fragmentation is avoided since a contiguous size of disk space is preallocated to the files and its contents stay together.

4 0
2 years ago
Determine of population size​
damaskus [11]

Answer:

there a 7 billion of people as of 2015 census

3 0
2 years ago
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