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Andru [333]
3 years ago
9

What’s the definition of prime

Mathematics
1 answer:
anzhelika [568]3 years ago
5 0

prime1

/prīm/

Learn to pronounce

See definitions in:

All

Mathematics

Religion

Printing

Fencing

Weapons

Building

Mechanics

Motoring

Biochemistry

adjective

1.

of first importance; main.

"her prime concern is the well-being of the patient"

Similar:

main

chief

key

primary

central

principal

foremost

first

most important

paramount

major

dominant

supreme

overriding

cardinal

preeminent

ultimate

number-one

fundamental

basic

essential

elemental

vital

Opposite:

secondary

subordinate

2.

of the best possible quality; excellent.

"prime cuts of meat"

Similar:

top-quality

highest quality

top

top-tier

best

first-class

first-rate

high-grade

grade A

superior

supreme

flawless

choice

select

finest

superlative

peak

optimal

model

excellent

marvelous

magnificent

superb

fine

wonderful

exceptional

formidable

top of the range

top of the line

tip-top

A1

stellar

top-notch

Opposite:

inferior

noun

1.

a state or time of greatest strength, vigor, or success in a person's life.

"you're in the prime of life"

Similar:

heyday

best days/years

day

time

prime of one's life

maturity

youth

springtime

salad days

bloom

flowering

full flowering

perfection

peak

pinnacle

height

high point/spot

zenith

ascendancy

2.

CHRISTIAN CHURCH

a service forming part of the Divine Office, traditionally said (or chanted) at the first hour of the day (i.e., 6 a.m.), but now little used.

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Someone please help me
allsm [11]

Answer:

Solutions: x = \frac{-3}{ 4} + i \sqrt{39},  x = \frac{-3}{4} - i \sqrt{39}

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}

x = \frac{-3 +/- \sqrt{3^{2} - 4(2)(6)} }{2(2)}

x = \frac{-3 +/- \sqrt{9- 48} }{4}

x = \frac{-3 +/- \sqrt{-39} }{4}

x = \frac{-3 + i \sqrt{39} }{4}, x = \frac{-3 - i \sqrt{39} }{4}

Therefore, the solutions to the given quadratic equation are:

x = -\frac{3}{ 4} + i \sqrt{39} ,   x = -\frac{3}{4} - i \sqrt{39}

4 0
3 years ago
Find the missing value when given the modulus.
kolbaska11 [484]

Solving the complex number, we get the value of the missing value that is ‘a’ = -6

We  have been given the expression as

          |a – i| = √37          (1)

Which is an expression of complex number. The general expression of complex number is given as

    z = x + iy

 where x is the real part and iy is the imaginary part

To find the modulus value, the formula is given by,

  |z| = |x + iy|

   |z| = √[(real part)2 + (imaginary part)2]

 |z| = √(x2 + y2)

According to the question, |z| = √37         (2)

Equating equation (1) and (2), we get

√(a2 + 1) = √37

(a2 + 1) = 37

a2 = 37 – 1

a2 = 36

a = √36

a = ±6

Now value of a can be 6 or -6. We have been given that the modulus is in third quadrant.

Hence the value will be negative. Therefore, the missing value will be -6.

Learn more about complex number here : brainly.com/question/5564133

#SPJ9

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2 years ago
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Mrrafil [7]
D = r• t
reverses the equation so that D and r are on the same side
d/r = t
200 \div 50 = 4
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If 24 is a solutoin of x, n has to be 24 squared. 24*24=576

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