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3 years ago

13

Is this table a function?

1 answer:

IrinaVladis [17]3 years ago

6 0

B is the correct answer because -3 is the only value x is multiplied by.

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Can someone please help me solve this

Lady_Fox [76]

The "parent function" is y = (log to the base 2 of) x

The domain of this function is (0, infinity) (all real numbers greater than zero).

The range of this function is the same as above.

If you replace "x" with "x+1" in the parent function, the associated graph will look the same as that of the given function, EXCEPT that it will be translated by 1 unit to the left.

After this has happened, that "-3" will shift the entire new graph downward by 3 units.

4 0

4 years ago

If -3m + 1 > 7, which of the following is a solution set for m?

Papessa [141]

ANSWER

m < -2

EXPLANATION

We want to find the solution set for m in:

$-3m+1>7$

First, collect like terms:

$\begin{gathered} -3m>7-1 \\ -3m>6 \end{gathered}$

Now, divide both sides by -3. When you divide an inequality by a negative number, <em>the sign changes direction</em>:

$\begin{gathered} \frac{-3m}{-3}>\frac{6}{-3} \\ m$

This means that all values of m must be less than -2.

<em>None of the options contains the correct solution set.</em>

4 0

1 year ago

HELP ME PLZ ILL GIVE U EXTRA POINTS

likoan [24]

Answer:

10 32 -9

10 -13 18

-9 -8 11

hope this helps

6 0

3 years ago

An equation parallel and perpendicular to 4x+5y=19

UNO [17]

Answer:

Parallel line:

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

$y=\frac{5}{4}x-\frac{1}{2}$

Step-by-step explanation:

we are given equation 4x+5y=19

Firstly, we will solve for y

$4x+5y=19$

we can change it into y=mx+b form

$5y=-4x+19$

$y=-\frac{4}{5}x+\frac{19}{5}$

so,

$m=-\frac{4}{5}$

Parallel line:

we know that slope of two parallel lines are always same

so,

$m'=-\frac{4}{5}$

Let's assume parallel line passes through (1,1)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-1=-\frac{4}{5}(x-1)$

now, we can solve for y

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

we know that slope of perpendicular line is -1/m

so, we get slope as

$m'=\frac{5}{4}$

Let's assume perpendicular line passes through (2,2)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-2=\frac{5}{4}(x-2)$

now, we can solve for y

$y=\frac{5}{4}x-\frac{1}{2}$

4 0

3 years ago

PLEASE HELP WITH GRAPH LAST QUESTION I NEED

SVETLANKA909090 [29]

Answer:

$\sf g(x) = -1(x+3)^2 -2$

Explanation:

$\sf original \ graph: \ y=-x^{2}$

the graph is translated 3 units to the left and 2 units down.

vertex: (-3,-2) point: (-1,-6)

$\sf so \ new \ graph :$

$\sf y = a(x-h)^2 +k$

$\sf -6 = a(-1-(-3))^2 -2$

$\sf -6 = 4a -2$

$\sf 4a = -4$

$\sf a = -1$

$\sf equation:$

$\sf y = a(x-h)^2 +k$

$\sf y = -1(x+3)^2 -2$

6 0

2 years ago

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