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Ostrovityanka [42]

3 years ago

12

You really want to earn an a in a class, but you still need to take one more test. suppose that your previous test scores are 85

, 95, and 79. assume that the test is out of 100 points. what score would you need to get on the last test? explain.

1 answer:

Alex787 [66]3 years ago

7 0

If u get 100 your average will be 89.75 which rounds up to a 90

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Help!!!! me please the first to answer will get brainliest!!!! please help me<br><br><br>

never [62]

<h3>1 Answer: v = -130</h3>

=============================================================

Explanation:

Because we're given multiple choices to pick from, we can go through each to do trial and error.

For instance, if v = 52, then

v/13 < -7

52/13 < -7

4 < -7

but that's a false statement since 4 is not smaller than -7. Use a number line to see this. You should have -7 to the left of 4, showing that -7 is the smaller value.

Because 4 < -7 is false, this means v/13 < -7 is false when v = 52. This rules out v = 52. You should find that v = 26 and v = -39 won't work for similar reasons.

Only v = -130 works since...

v/13 < -7

-130/13 < -7

-10 < -7

This is true because -10 is to the left of -7 on the number line.

-------------------------------------------------

Another approach:

We have some unknown number v, and we're dividing by 13 to get the expression v/13. To undo this, we multiply both sides by 13

v/13 < -7

13*(v/13) < 13*(-7) .... multiply both sides by 13

v < -91

So any solution to the original inequality must be smaller than -91. This allows us to rule out v = 52, v = 26 and v = -39.

The value v = -130 is smaller than -91, so it satisfies v < -91. Therefore, v = -130 is a solution to the original inequality.

6 0

3 years ago

Would it still be 3.19? Because you don't need to round to 3.20 because 3.192 <--- the 2 won't do anything.. If it's 5 or hig

Leviafan [203]

Yes, remember this 4 or less let it rest, 5 or more let it soar.

7 0

3 years ago

Picture attached below. Please help.

Anuta_ua [19.1K]

There isnt a picturee but when you add another question I will hep you the best I can :)

4 0

3 years ago

Read 2 more answers

PLEASE MATH HELP WILL GIVE BRAINLIEST!!

solong [7]

I'm sorry!!!!
where is the x?!

7 0

3 years ago

Read 2 more answers

5. If position of object x = 3 sinΘ – 7 cosΘ then motion of object is bounded between position.

lesya692 [45]

9514 1404 393

Answer:

±√58 ≈ ±7.616

Step-by-step explanation:

The linear combination of sine and cosine functions will have an amplitude that is the root of the sum of the squares of the individual amplitudes.

|x| = √(3² +7²) = √58

The motion is bounded between positions ±√58.

_____

Here's a way to get to the relation used above.

The sine of the sum of angles is given by ...

sin(θ+c) = sin(θ)cos(c) +cos(θ)sin(c)

If this is multiplied by some amplitude A, then we have ...

A·sin(θ+c) = A·sin(θ)cos(c) +A·cos(θ)sin(c)

Comparing this to the given expression, we find ...

A·cos(c) = 3 and A·sin(c) = -7

We know that sin²+cos² = 1, so the sum of the squares of these values is ...

(A·cos(c))² +(A·sin(c))² = A²(cos(c)² +sin(c)²) = A²(1) = A²

That is, A² = (3)² +(-7)² = 9+49 = 58. This tells us the position function can be written as ...

x = A·sin(θ +c) . . . . for some angle c

x = (√58)sin(θ +c)

This has the bounds ±√58.

3 0

3 years ago