Find the value of the variable. Please and thank u
1 answer:
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The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.
<h3>How to identify similar triangles?</h3>From the image attached, we see that we are given the Parallelogram GRPC. Thus;
A. The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.
B. The proof of the fact that ΔGCB and ΔPEB are similar pairs of triangles is as follow;
∠CGB ≅ ∠PEB (Alternate Interior Angles)
∠BPE ≅ ∠BCG (Alternate Interior Angles)
∠GBC ≅ ∠EBP (Vertical Angles)
C. To find the distance from B to E and from P to E, we will first find PE and then BE by proportion;
225/325 = PE/375
PE = 260 ft
BE/425 = 225/325
BE = 294 ft
Read more about Similar Triangles at; brainly.com/question/14285697
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Answer:
The first option,
Step-by-step explanation:
Because the graph is showing a quadratic function we need to start by the equation of a quadratic function in its vertex form, which is:
, where:
a= is a transformation coefficient
(h,k)=vertex coordinates
Because the vertex is (2,1) then h=2 and k=1, using the vertex form we obtain:
Now, because we have an extra point (0,5), we can find 'a' as follows:
, which can be simplified as:
Then the vertex form of the graph is:
, which is the first option.