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IrinaK [193]
3 years ago
12

Solving Equations 3k+10=2k-21

Mathematics
1 answer:
Nikolay [14]3 years ago
6 0

3k+10=2k-21

move 2k to the other side

sign changes from +2k to -2k

3k-2k+10=2k-2k-21( combine like terms)

3k-2k+10= -21

k+10=-21

move +10 to the other side

k+10-10= -21-10

k= -21-10

answer:

k= -31

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I would believe it to be 22
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Describe and correct the error in finding the area of a sector with a radius of 6 centimeters and a central angle of 40
Jet001 [13]

Answer:

12.56

Step-by-step explanation:

Remark

Since we don't have anything other than the question, all I can do is answer the question. You are left with the task of figuring out the error.

Formula

Area = (central angle divided by 360 ) * pi r^2

Solution

Area = (40 /360) * 3.14 * 6^2

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8 0
3 years ago
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0
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57 students choose to attend one of three after school activities: football, tennis or running.
skelet666 [1.2K]

The probability that the randomly selected student chose running is; 12/57

<h3>Solving Probability Questions</h3>

Total number of students = 57

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Thus, probability that a randomly selected student chose running = 12/57

Read more about probability selection at; brainly.com/question/251701

3 0
3 years ago
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