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IrinaK [193]
3 years ago
12

Solving Equations 3k+10=2k-21

Mathematics
1 answer:
Nikolay [14]3 years ago
6 0

3k+10=2k-21

move 2k to the other side

sign changes from +2k to -2k

3k-2k+10=2k-2k-21( combine like terms)

3k-2k+10= -21

k+10=-21

move +10 to the other side

k+10-10= -21-10

k= -21-10

answer:

k= -31

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I neee help plss i have so lil time to hand it in
SashulF [63]

The Solution.

The given equation is

\begin{gathered} y=|x|+7 \\ \text{Where x=11} \end{gathered}

Substituting 11 for x, we can get the value of y.

\begin{gathered} y=|11|+7 \\ y=11+7 \\ y=18 \end{gathered}

Hence, the value of y is 18.

5 0
1 year ago
Evaluate the expression 2b to the third power+ 5 when b=5
Andrej [43]

Answer:

1005

Step-by-step explanation:

10 to the third power + 5 =

1000 + 5 =

1005

Hope that helps!

7 0
3 years ago
Given that the expression 2x^3 + mx^2 + nx + c leaves the same remainder when divided by x -2 or by x+1 I prove that m+n =-6
Alla [95]

Given:

The expression is:

2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1.

To prove:

m+n=-6

Solution:

Remainder theorem: If a polynomial P(x) is divided by (x-c), thent he remainder is P(c).

Let the given polynomial is:

P(x)=2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1. By using remainder theorem, we can say that

P(2)=P(-1)              ...(i)

Substituting x=-1 in the given polynomial.

P(-1)=2(-1)^3+m(-1)^2+n(-1)+c

P(-1)=-2+m-n+c

Substituting x=2 in the given polynomial.

P(2)=2(2)^3+m(2)^2+n(2)+c

P(2)=2(8)+m(4)+2n+c

P(2)=16+4m+2n+c

Now, substitute the values of P(2) and P(-1) in (i), we get

16+4m+2n+c=-2+m-n+c

16+4m+2n+c+2-m+n-c=0

18+3m+3n=0

3m+3n=-18

Divide both sides by 3.

\dfrac{3m+3n}{3}=\dfrac{-18}{3}

m+n=-6

Hence proved.

7 0
3 years ago
6i-5=-17 what does i equal
vagabundo [1.1K]

Answer:

-2

Step-by-step explanation:

6i-5=-17

6i=-17+5

6i=-12

i=-12/6

i=-2

7 0
3 years ago
Read 2 more answers
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Scilla [17]
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3 years ago
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