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IrinaK [193]
4 years ago
12

Solving Equations 3k+10=2k-21

Mathematics
1 answer:
Nikolay [14]4 years ago
6 0

3k+10=2k-21

move 2k to the other side

sign changes from +2k to -2k

3k-2k+10=2k-2k-21( combine like terms)

3k-2k+10= -21

k+10=-21

move +10 to the other side

k+10-10= -21-10

k= -21-10

answer:

k= -31

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Answer:

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Question number 9
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Question number 10
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3 years ago
The terminal side of Ø is in quadrant II and cos ø = -5/13 What is sin ø?
Sliva [168]

the value of sin ∅ is 12/ 13

<h3>Quadrants and the "cast" Rule:</h3>
  • In the first quadrant, the values for sin, cos, and tan are positive.
  • In the second quadrant, the values for sin are positive only.
  • In the third quadrant, the values for tan are positive only.
  • In the fourth quadrant, the values for cos are positive only.

From the given question,

We have,  cos ∅= 5/13

From the trigonometric identities, we have that

sin^2\alpha  + cos^2\alpha  = 1

Then , let's substitute the value of cos ∅

sin^2\alpha +(\frac{-5}{13} )^2 = 1

Let make sin the subject of formula and find the squares of the fraction

sin²∅ = 1 - \frac{25}{169}

Find the LCM

sin²∅ = \frac{169 - 25}{169}

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sin ∅ = 12/ 13

Thus, the value of sin ∅ is 12/ 13

Learn more about quadrant  here:

brainly.com/question/863849

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1.Solve using square roots.
ElenaW [278]

Answer:

see explanation

Step-by-step explanation:

1

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x = - 5 ± 2, thus

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2

(x + 6)² = 7 ( take the square root of both sides )

x + 6 = ± \sqrt{7} ( subtract 6 from both sides )

x = - 6 ± \sqrt{7}, thus

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x = 2 + 3\sqrt{2}

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