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SSSSS [86.1K]
1 year ago
12

I neee help plss i have so lil time to hand it in

Mathematics
1 answer:
SashulF [63]1 year ago
5 0

The Solution.

The given equation is

\begin{gathered} y=|x|+7 \\ \text{Where x=11} \end{gathered}

Substituting 11 for x, we can get the value of y.

\begin{gathered} y=|11|+7 \\ y=11+7 \\ y=18 \end{gathered}

Hence, the value of y is 18.

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Write in simplest form:<br> <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24a%5E%7B10%7Db%5E%7B6%7D%7D" id="TexFormula1" ti
Charra [1.4K]

Answer:

2a^3b^2\sqrt[3]{3a}

Step-by-step explanation:

Use the following rules for exponents:

a^m*a^n=a^{m+n}\\\\\sqrt[3]{x^3}=x

Simplify 24. Find two factors of 24, one of which should be a perfect cube:

8*3=24\\\\2^3=8

Insert:

\sqrt[3]{2^3*3a^{10}b^6}

Now split the exponents. Split 10 into as many 3's as possible:

10=3+3+3+1

Insert as exponents:

\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^6}

Split 6 into as many 3's as possible:

6=3+3

Insert as exponents:

\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^3*b^3}

Now simplify. Any terms with an exponent of 3 will be moved out of the radical (rule #2):

2\sqrt[3]{3*a^3*a^3*a^3*a^1*b^3*b^3}\\\\\\2*a*a*a\sqrt[3]{3*a^1*b^3*b^3}\\\\\\2*a*a*a*b*b\sqrt[3]{3*a^1}

Simplify:

2a^3b^2\sqrt[3]{3a}

:Done

6 0
2 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%3De%5E%7B3x%7D%20.sinx" id="TexFormula1" title="f(x)=e^{3x} .sinx" alt="f(x)=e^{3x} .
Maslowich

Answer:

6

Step-by-step explanation:

đạo hàm cấp 2 của f(x) rồi thế 0 vào

8 0
2 years ago
Which table represents a linear function?
igomit [66]

Answer:

Table 2

Step-by-step explanation:

I've done simular problems

6 0
2 years ago
What does n equal in 2n+33
lana66690 [7]
N= -16.5

Subtract 33 then divide by 2
2n=-33
n=-33/2 or n=-16.5
4 0
2 years ago
Will give brainliest!!!!!!! Please help I need correct answer!!!
andreyandreev [35.5K]

Answer:

The answer is "was the first time the Constitution defined what a citizen is"

does this help?

8 0
2 years ago
Read 2 more answers
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