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3 years ago

Need help...,.......

Mathematics

1 answer:

never [62]3 years ago

7 0

3x
= -------------
3y<span>√2
</span>
x
= -------------
y√2

x√2
= -------------
2y

Answer is A. first choice

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Anne deposited $500 in an account that earns 6% simple annual interest. Shelly deposited $500 in an account that earns 6% annual

Inga [223]

Answer:

It is clear that, The Shelly account is $11.23 more than that in Anne account .

Step-by-step explanation:

Given as :

For Anne

The amount deposited in account = p = $500

The rate of interest = r = 6% at simple interest

The time period of deposit = t = 4 years

Let The amount received in account after 4 years = $ $A_1$

<u>From Simple Interest method</u>

Simple Interest = $\dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}$

Or, s.i = $\dfrac{\textrm p\times \textrm r\times \textrm t}{100}$

Or, s.i = $\dfrac{\textrm 500\times \textrm 6\times \textrm 4}{100}$

Or, s.i = $\dfrac{12000}{100}$

i.e s.i = $120

∵ Amount = Principal + Interest

Or, $A_1$ = p + s.i

Or $A_1$ = $500 + $120

Or, Amount = $620

So, The Amount in Anne account after 4 years is $620

Again

For, Shelly

The amount deposited in account = P = $500

The rate of interest = R = 6% compounded annually

The time period of deposit = T = 4 years

Let The amount received in account after 4 years = $ $A_2$

<u>From Compound Interest method</u>

Amount = Principal × $(1+\dfrac{\textrm rate}{100})^{\textrm time}$

Or, $A_2$ = P × $(1+\dfrac{\textrm R}{100})^{\textrm T}$

Or, $A_2$ = $500 × $(1+\dfrac{\textrm 6}{100})^{\textrm 4}$

Or, $A_2$ = $500 × $(1.06)^{4}$

Or, $A_2$ = $500 × 1.26247

Or, $A_2$ = $631.23

So, The amount received by Shelly in her account after 4 years = $631.23

Now, Difference between amount received in their account

i.e $A_2$ - $A_1$ = $631.23 - $620

Or, $A_2$ - $A_1$ = $11.23

Hence, It is clear that, The Shelly account is $11.23 more than that in Anne account . Answer

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3 years ago

Steve washed 15 cars in 3 hours.how many cars can he wash in 7 hours?

DanielleElmas [232]

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3 years ago

Which line is parallel to the line<br> shown below?

Travka [436]

<h3>Answer: Choice D</h3>

4x - 3y = 15

====================================================

Explanation:

The two points (-1,-1) and (2,3) are marked on the line

Let's find the slope of the line through those two points.

$(x_1,y_1) = (-1,-1) \text{ and } (x_2,y_2) = (2,3)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{3 - (-1)}{2 - (-1)}\\\\m = \frac{3 + 1}{2 + 1}\\\\m = \frac{4}{3}\\\\$

The slope is 4/3 meaning we go up 4 and to the right 3.

-------------

Parallel lines have equal slopes, but different y intercepts. We'll need to see which of the four answer choices have a slope of 4/3.

Solve the equation in choice A for y. The goal is to get it into y = mx+b form so we can determine the slope m.

$3x + 4y = -4\\\\4y = -3x-4\\\\y = -\frac{3}{4}x-\frac{4}{4}\\\\y = -\frac{3}{4}x-1$

Equation A has a slope of -3/4 and not 4/3 like we want.

Therefore, this answer choice is crossed off the list.

Follow similar steps for choices B through D. I'll show the slopes of each so you can check your work.

slope of equation B is 3/4
slope of equation C is -4/3
slope of equation D is 4/3

We have a match with equation D. Therefore, the equation 4x-3y = 15 is parallel to the given line shown in the graph.

You can use graphing tools like Desmos or GeoGebra to confirm the answer.

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1 year ago