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trapecia [35]
3 years ago
10

Need help...,.......

Mathematics
1 answer:
never [62]3 years ago
7 0
         3x
= -------------
       3y<span>√2
</span>         
         x
= -------------
       y√2  

         x√2
= -------------
         2y
  
Answer is A. first choice
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Y=(1/2 x)-2

My Work:
Say that the slop is "a" and that the y-intercept is "b".

For the slope:
First coordinate equation: -3=-2a+b
Second coordinate equation: -1=2a+b
Combine the equations. -3-(-1)=-2a-(2a)+b-(b)
Break down the parenthesis. -3+1=-2a-2a+b-b
Simplify the equation. -2=-4a
Divide both sides by -4 to get the answer to the slope. a=1/2

For the y-intercept:
Use the second coordinate's equation and the now known slope. -3=-2*1/2+b
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3 years ago
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A line through the origin and (10,4) is showin in the standard (x,y) coordinate plane below. The acute angle between the line an
Snowcat [4.5K]

Answer:

\cos\theta=\frac{10}{\sqrt{116}}

Step-by-step explanation:

To solve this, we can imagine a line drawn directly down from the point (10,4) to the x-axis. This would make a right triangle with length 10 and height 4.

\cos\theta is equal to the length of adjacent leg to the angle divided by the length of the hypotenuse of the triangle. From the picture, we can see the adjacent leg is 10.

We can use Pythagorean's Theorem to find the hypotenuse (let c represent the length of the hypotenuse):

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100+16=c^2

116=c^2

c=\sqrt{116}

Thus, we know the adjacent is 10, and the hypotenuse is \sqrt{116}. This means \cos\theta=\frac{10}{\sqrt{116}}.

Hope this helps!

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Answer:

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Step-by-step explanation:

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