Answer: 15309
hope this helps, the nth term calulation is (7/3) times 3^n
You have to use distributive property then you combine like terms
Answer:
B. 88.8
Step-by-step explanation:
let x represent class y
(x+71.2)/2=80 multiply each side by 2
x+71.2=160 subtract 71.2 by both sides
x=88.8
or
trial an error
replace x with each of the numbers and see if it plugs in.
example:
(80.5+71.2)/2=80
151.7/2=80
75.85=80?
false. incorrect
another example:
(88.8+71.2)/2=80
160/2=80
80=80?
true. correct
Answer: x=9
Step-by-step explanation:
The bottom triangle that has a 40° is an isosceles triangle, therefore the other angle at the bottom right is also 40°. This leaves the top angle to be 100°.
180=40+40+x
180=80+x
x=100
Now, to find ∠2, you can tell it is a supplementary angle. Therefore, the 2 angles add up to 180°
180-100=∠2
80°=∠2
The problem states that ∠2 is 9x-1. We know that ∠2 is 80°. We can solve for x.
80=9x-1
81=9x
x=9
Answer:
<h2>Option A is the answer(here the answer is calculated taking the whole value, without approximating it to a nearest value)</h2>
Step-by-step explanation:
Annual interest rate is 2.75%. Hence, the monthly interest rate is 
The amount will be compounded 
times.
Every month they deposits $500.
In the first month that deposited $500 will be compounded 240 times.
It will be ![500\times [1 + \frac{2.75}{1200} ]^{240}](https://tex.z-dn.net/?f=500%5Ctimes%20%5B1%20%2B%20%5Cfrac%7B2.75%7D%7B1200%7D%20%5D%5E%7B240%7D)
In the second month $500 will be deposited again, this time it will be compounded 239 times.
It will give ![500\times [1 + \frac{2.75}{1200} ]^{239}](https://tex.z-dn.net/?f=500%5Ctimes%20%5B1%20%2B%20%5Cfrac%7B2.75%7D%7B1200%7D%20%5D%5E%7B239%7D)
Hence, the total after 20 years will be ![500\times [1 + \frac{2.75}{1200} ]^{240} + 500\times [1 + \frac{2.75}{1200} ]^{239} + ........+ 500\times [1 + \frac{2.75}{1200} ]^{1} = 160110.6741](https://tex.z-dn.net/?f=500%5Ctimes%20%5B1%20%2B%20%5Cfrac%7B2.75%7D%7B1200%7D%20%5D%5E%7B240%7D%20%2B%20500%5Ctimes%20%5B1%20%2B%20%5Cfrac%7B2.75%7D%7B1200%7D%20%5D%5E%7B239%7D%20%2B%20........%2B%20500%5Ctimes%20%5B1%20%2B%20%5Cfrac%7B2.75%7D%7B1200%7D%20%5D%5E%7B1%7D%20%3D%20160110.6741)
