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Klio2033 [76]
3 years ago
6

How much greater is this week’s median temperature than last week’s median temperature?

Mathematics
1 answer:
Scrat [10]3 years ago
5 0

Answer:

5 degrees

Step-by-step explanation:

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12(x-6)and 14(x+14).<br><br> plz help
il63 [147K]

Answer:

138 and 210?

Step-by-step explanation:

8 0
3 years ago
What is the equation of the line perpendicular to the line y =4/9 x – 2 that passes through the point (4,3)?
Scrat [10]
Line y = 4/9 x - 2 has a slope of 4/9.
For perpendicular lines, the ploduct of the two slopes is -1. Thus the slope of the required line is -1/(4/9) = -9/4

Equation of a line is given by y - y1 = m(x - x1)
y - 3 = -9/4(x - 4)
y - 3 = -9/4 x + 9
y = -9/4 x + 9 + 3
y = -9/4 x + 12.
4 0
4 years ago
Read 2 more answers
Word problem
Serjik [45]

Find the price per can for each place. Village Market : $2.30 per 5 cans= $0.46 per can. Sam's Club: $4.30/10 cans = $0.43 per can.  $0.43 per can at Sam's Club is less than $0.46 per can at Village Market, so Sam's Club is the better buy.

6 0
3 years ago
Read 2 more answers
# of faces?<br> # of edges?<br> # of vertices?<br> HELP (links= report)
lara [203]

Step-by-step explanation:

Face is 5 the edges is 10 the vertices is 12

4 0
3 years ago
Willing to brainlist solve 16-17 please during this exam
ivann1987 [24]

Answer:

16. B

17. B

Step-by-step explanation:

16. The intercept form of the parabola is

y=a(x-x_1)(x-x_2),

where x_1, x_2 are two x-intercepts.

In your case,

x_1=2\\ \\x_2=-8

so

y=a(x-2)(x-(-8))\\ \\y=a(x-2)(x+8)

To find <em>a</em>, substitute coordinates of the point (-6,-4) parabola is passing through

-4=a(-6-2)(-6+8)\\ \\-4=-16a\\ \\a=\dfrac{1}{4}

and

y=\dfrac{1}{4}(x-2)(x+8)

17. The vertex form of the parabola equation is

-2p(y-k)=(x-h)^2,

where <em>(h,k)</em> are the coordinates of the vertex and sign "-" because parabola goes down.

In your case, vertex is (2,3), so

-2p(y-3)=(x-2)^2

The vertex is 3 units from the focus, then

\dfrac{p}{2}=3\\ \\p=6

The equation of the parabola is

-2\cdot 6(y-3)=(x-2)^2\\ \\y=-\dfrac{1}{12}(x-3)^2+3

8 0
4 years ago
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