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Lelu [443]
3 years ago
8

How many batting lineups are there for nine players of a baseball team if the center fielder must bat fourth, the second baseman

must bat third and the pitcher last?
Mathematics
1 answer:
OLga [1]3 years ago
4 0

The number of possible batting lineups is 720

<u><em>Explanation</em></u>

Total number of players in the team = 9

The center fielder must bat fourth, the second baseman must bat third and the pitcher last. That means, <u>3 slots in the batting line-up are already assigned to 3 players</u>.

So, the remaining (9 - 3) = 6 players will be assigned to remaining 6 slots.

Thus, the possible number of ways so that 6 players can be assigned to 6 slots will be:  6! = 6*5*4*3*2*1=720

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<h3>Answer: 5.86÷12=0.5 in nearest penny </h3><h3> </h3><h3>Step-by-step explanation: </h3><h3>this number kind of problem u solve it using inversely proportional method one one quantity is decreasing which is the ounce</h3>

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What is the area of a rectangles with the side lengths 5 inches and 1/3 inches? ​
sveticcg [70]

Answer:

area of a rectangle is length multiplied by breath, which is the multiplication of 5 an 1/3

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3 years ago
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3 years ago
Given f(x) = the quantity of 2x minus 2 divided by 4, solve for f−1(3).
spin [16.1K]
Given: f(x)=(2x-2)/4
find f^-1(3)?
we need to find the inverse of f(x), so
x=(2y-2)/4
2y-2=4x
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y=2x+1
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6 0
3 years ago
Simplify expression x8y-26/x14y-5 × x-39y-21
koban [17]

The simplified form of the expression is x^{-45} y^{-42}

<h3>Simplifying an expression</h3>

From the question, we are to simplify the given expression

The given expression is

\frac{x^{8}y^{-26}  }{x^{14}y^{-5}  } \times x^{-39} y^{-21}

The expression can be simplified as shown below

\frac{x^{8}y^{-26}  }{x^{14}y^{-5}  } \times x^{-39} y^{-21}

\frac{x^{8} \times x^{-39} \times  y^{-26} \times  y^{-21}  }{x^{14} \times y^{-5}  }

\frac{x^{8+-39} \times  y^{-26+-21}  }{x^{14} \times y^{-5}  }

\frac{x^{8-39} \times  y^{-26-21}  }{x^{14} \times y^{-5}  }

\frac{x^{-31} \times  y^{-47}  }{x^{14} \times y^{-5}  }

Then,

\frac{x^{-31} }{x^{14} } \times \frac{ y^{-47} }{ y^{-5} }

x^{-31-14} \times y^{-47--5}

x^{-31-14} \times y^{-47+5}

x^{-45} \times y^{-42}

x^{-45} y^{-42}

Hence, the simplified form of the expression is x^{-45} y^{-42}

Learn more on Simplifying an expression here: brainly.com/question/2320607

#SPJ1

3 0
2 years ago
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