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Lelu [443]
3 years ago
8

How many batting lineups are there for nine players of a baseball team if the center fielder must bat fourth, the second baseman

must bat third and the pitcher last?
Mathematics
1 answer:
OLga [1]3 years ago
4 0

The number of possible batting lineups is 720

<u><em>Explanation</em></u>

Total number of players in the team = 9

The center fielder must bat fourth, the second baseman must bat third and the pitcher last. That means, <u>3 slots in the batting line-up are already assigned to 3 players</u>.

So, the remaining (9 - 3) = 6 players will be assigned to remaining 6 slots.

Thus, the possible number of ways so that 6 players can be assigned to 6 slots will be:  6! = 6*5*4*3*2*1=720

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Answer:

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Assuming that there are no hidden cubes, what is the front orthographic view of the diagram?
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