How many batting lineups are there for nine players of a baseball team if the center fielder must bat fourth, the second baseman
1 answer:
The number of possible batting lineups is 720
<u><em>Explanation</em></u>
Total number of players in the team = 9
The center fielder must bat fourth, the second baseman must bat third and the pitcher last. That means, <u>3 slots in the batting line-up are already assigned to 3 players</u>.
So, the remaining (9 - 3) = 6 players will be assigned to remaining 6 slots.
Thus, the possible number of ways so that 6 players can be assigned to 6 slots will be:
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Answer:
(47.3, 54.1)
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
That is z with a pvalue of , so Z = 1.96.
Now, find the margin of error M as such
In which is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 50.7 - 3.4 = 47.3
The upper end of the interval is the sample mean added to M. So it is 50.7 + 3.4 = 54.1
The answer is (47.3, 54.1).