How many batting lineups are there for nine players of a baseball team if the center fielder must bat fourth, the second baseman
1 answer:
The number of possible batting lineups is 720
<u><em>Explanation</em></u>
Total number of players in the team = 9
The center fielder must bat fourth, the second baseman must bat third and the pitcher last. That means, <u>3 slots in the batting line-up are already assigned to 3 players</u>.
So, the remaining (9 - 3) = 6 players will be assigned to remaining 6 slots.
Thus, the possible number of ways so that 6 players can be assigned to 6 slots will be:
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Answer:
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Step-by-step explanation:
73.
18 = 3x (divide both sides by 3 )
6 = x ( multiply both sides by
)
6 = 3x [
×
= 3 ]
divide both sides by 3
x = 2
74.
24 = 2x ( divide both sides by 2 )
12 = x ( multiply both sides by
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12 = 2x ( divide both sides by 2 )
x = 6
75.
9 × x = 18
( divide both sides by 9
)
x = 2
76.
2 = x × ( multiply both sides by
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2 = 4x ( divide both sides by 4 )
x =